Question

A group of 3 adults and 5 children pay a total of 52$ for movie tickets

Answer 1

Answer:

• $9 adult
• $5 child

Step-by-step explanation:

Letting "a" and "c" represent the costs of adult tickets and child tickets, the problem statement gives us two relations:

  3a +5c = 52

  2a +4c = 38

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We can solve this system of equations using "elimination" as follows:

Dividing the first equation by 2 we get

  a +2c = 19

Multiplying this by 3 and subtracting the first equation eliminates the "a" variable and tells us the price of a child ticket:

  3(a +2c) -(3a +4c) = 3(19) -(52)

  c = 5 . . . . . . collect terms

  a +2·5 = 19 . . substitute for c in the 3rd equation above

  a = 9 . . . . . . subtract 10

One adult ticket costs $9; one child ticket costs $5.