Answer:
A =576 pi in ^2
Step-by-step explanation:
Circumference is given by
C = 2 * pi *r
48 pi = 2 * pi *r
divide by 2 pi
48 pi /2 pi = 2 * pi * r / 2 pi
24 = r
We can find the area by
A = pi r^2
A = pi (24)^2
A =576 pi in ^2
(a) 4
(b) y = sqrt(9 - (9/16)x^2)
The best guess to the formula using knowledge of the general formula for an ellipse is:
x^2/16 + y^2/9 = 1
(a). An ellipse is reflectively symmetrical across both the major and minor axis. So if you can get the area of the ellipse in a quadrant, then multiplying that area by 4 would give the total area of the ellipse. So the factor of 4 is correct.
(b). The general equation for an ellipse is not suitable for a general function since it returns 2 y values for every x value. But if we restrict ourselves to just the positive value of a square root, that problem is easy to solve. So let's do so:
x^2/16 + y^2/9 = 1
x^2/16 + y^2/9 - 1 = 0
x^2/16 - 1 = - y^2/9
-(9/16)x^2 + 9 = y^2
9 - (9/16)x^2 = y^2
sqrt(9 - (9/16)x^2) = y
y = sqrt(9 - (9/16)x^2)
Hey there!
150 = 8x + 6y
↠ 150 = 8x + 6(9)
↠ 8x + 6(9) = 150
↠ 8x + 54 = 150
SUBTRACT 54 to BOTH SIDES
8x + 54 - 54 = 150 - 54
CANCEL out: 54 - 54 because that gives you 0
KEEP: 150 - 54 because helps solve for x
↣150 - 54 = 96↢
NEW EQUATION: 8x = 96
DIVIDE 8 to BOTH SIDES
8x/8 = 96/8
CANCEL out: 8/8 because that gives you 1
KEEP: 96/8 because that gives the value of x
96/8 = x
x = 12
Answer: x = 12
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
Height of the student=1.651m
Step-by-step explanation:
Given: Height of a student= 65.0 inch.
To find: Height of a student in meters.
Solution:
We know that 1 inch=2.54 cm, then
65.0 inch will be =
65.0 inch will be=
Also, we know that 1cm=
, then
165.2 cm will be equal to=
165.2 cm will be equal to=
Therefore, the height of a student in meters will be 1.651 meters.
Answer:
C)
Step-by-step explanation:
Prime factorization of 420 = 2 × 2 × 3 × 5 × 7 = 22 × 3 × 5 × 7.
If you take...
2 + 2 + 3 + 5 + 7...
You would get 17.
Hope this helps! :) Good Luck!
<em>-kiniwih426</em>
