The magnitude of the resulting vector, u - v, is approximately 5.83
and its angle of direction is approximately 59.04°.
<h3>How to find the magnitude of the resulting vector?</h3>
We want to subtract vector v from vector u.
We are given;
v = <2, -3> = 2i - 3j
u = <5, 2> = 5i + 2j
u - v = 5i + 2j - (2i - 3j)
= 5i + 2j - 2i + 3j
= 3i + 5j
Resultant vector = √(3² + 5²)
Resultant vector = √34 ≈ 5.83
Angle of direction of resultant vector is;
tan θ = (5/3)
θ = tan⁻¹(5/3)
θ = 59.04°
Read more about Magnitude of Vector at; brainly.com/question/3184914
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The way this problem is stated is that you put 1 grain of rice on the first square, the second square has 2 grains of rice. The third square has 4 grains of rice and you keep on doubling from there. When you tell me there is a 0 square, I'm not sure what you mean.
That would mean (to me) that square 1 has 2 grains of rice
Square 2 has 4 grains of rice
Square 3 has 8 grains of rice
The table goes up to 64 squares on a chess board.
2^64 which is (rounded) to about 1.84 with 17 zeros behind the 1.84.
My calculator says the answer is 1.84 * 10^19
I think you want
2^64<<<<<answer.
Or maybe
y =R(x) = 2^x <<<< answer.
where the domain is 0 <=x <= 64 contained in the integers.
Answer:
Step-by-step explanation:
![-4x^2+11x-6=-(4x^2-11x+6)=-(4x^2-8x-3x+6)\\\\=-\left[4x(x-2)-3(x-2)]=-(x-2)(4x-3)=(-4x+3)(x-2)](https://tex.z-dn.net/?f=-4x%5E2%2B11x-6%3D-%284x%5E2-11x%2B6%29%3D-%284x%5E2-8x-3x%2B6%29%5C%5C%5C%5C%3D-%5Cleft%5B4x%28x-2%29-3%28x-2%29%5D%3D-%28x-2%29%284x-3%29%3D%28-4x%2B3%29%28x-2%29)
Answer:
(a) The product of the sum of a and b and their difference.
(b) The tripled product of 6a and b².
(c) The difference of the squares of 2m and 7n.
Answer:
R
Step-by-step explanation:
