Answer:
The horizontal segment of E and vertical segments of M.
Step-by-step explanation:
Answer:
you are indeed correct
Step-by-step explanation: lol thanks for the points
Hello,
The formula for finding the area of a circular region is:

then:

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
Answer:
Step-by-step explanation:
The first thing you need to do is develop the equation. Less in this case means subtract.
On the left side you have
9 times a number which is 9*x
5 less than 9 times a number means 9x - 5
Now you shift to the right
x = 3
x + 19 What you get is
9x - 5 = x + 19 Subtract x from both sides of the equation
9x - x - 5 = 19 Combine both x terms on the left
8x - 5 = 19 Add 5 to both sides.
8x - 5 + 5 = 19 + 5 Combine terms
8x = 24 Divide by 8
x = 24/8
x = 3
Answer:5.4×105+2.3×104.
Step-by-step explanation: