if a b 9 are in GP
b÷a = 9 ÷ b
b^2 = 9a
if a - 1 b 9 are in AP
2b = a+8
b = a+8÷2
substitute
b is equal to a + 8 by 2 in b square equal to 9 a
(a+8÷2)^2 = 9a
a^2+16a+64 = 36a
a^2 -20a +64 =0
(a-16) (a-4) =0
a= 16 or a=4
when a=16 b= 12
when a=4 b= 6
Value of a and b are given above
Answer:
7/5 * A *y =k
Step-by-step explanation:
A=5k/7y
Multiply each side by 7y
A* 7y = 5k/7y * 7y
7Ay = 5k
Divide by 5
7Ay/5 = 5k/5
7/5 * A *y =k
76, 84, 93, 67, 82, 87, & 76
The mean is just the middle number of the data set,
Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93
Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93
So, in this case, the median is 82.
For every 7 votes for candidate a, there are 4 votes for candidate c
