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dalvyx [7]
3 years ago
11

Help !!!! Thank you!!!!

Mathematics
1 answer:
castortr0y [4]3 years ago
3 0

Answer:

Option (G)

Step-by-step explanation:

Volume of the real cane = 96 in³

Volume of the model of a can = 12 in³

Volume scale factor = \frac{\text{Volume of the model}}{\text{Volume of the real can}}

                                 = \frac{12}{96}

                                 =\frac{1}{8}

Scale factor of the model = \sqrt[3]{\text{Volume scale factor}}

                                          =\sqrt[3]{\frac{1}{8}}

                                          =\frac{1}{2}

Therefore, scale factor of the model of a can = \frac{1}{2} ≈ 1 : 2

Option (G) will be the correct option.

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7. Richard deposited $5400 and got back an amount of $6000 after 2 years.
sveticcg [70]

Answer:

600

Step-by-step explanation:

7 0
3 years ago
For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co
Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation \sigma = $7,500

\alpha = 1 - confidence interval = 1 - .95 = .05

Z_{\frac{\alpha}{2}} =  Z_{\frac{.05}{2}} = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

                           E   = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

         1000   =  Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}

n = 216

(c)   Margin of error ( E) = $500

   E = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

  500 = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}

n = 864

7 0
3 years ago
PLEASE HELP
Mandarinka [93]

Let x=large boxes and y=small boxes.

x+y=110

60x+35y=5100

____________

You need to cancel out one of the variables to solve for one. Let's cancel out y.

-35(x+y=110)


-35x-35y=-3850

60x+35y=5100

____________

Add the two equations.

25x=1250

x=50

_____________

Plug in 50 for x into one of the equations to solve for y.

50+y=110

y=60

_____________

50 large boxes

60 small boxes

5 0
3 years ago
Read 2 more answers
Please help!!! Thanks!
Darina [25.2K]
8x+(4*30)=6(6+30)
8x+120=6x+180
2x=60
x=30 pounds of coffee
3 0
3 years ago
Container A has a greater volume than Container B. Each container has a volume between 220 and 240 cubic inches. Use 3.14 for ?.
Yuri [45]

Answer:

220

Step-by-step explanation:

6 0
3 years ago
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