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3 years ago

Find the solutions to 40x2 – 140 = 500

Mathematics

1 answer:

Fofino [41]3 years ago

7 0

I suggest downloading Desmos! It’s an app and it will help a lot with algebra.

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Maki receives money from her relatives every year on her birthday. Last year, she received a total of $650. This year, she recei

BabaBlast [244]

Answer:

Step-by-step explanation:

percent increase = ((new number - original number) / (original number)) * 100

= ((910 - 650) / 650) * 100

= (260 / 650) * 100

= 0.4 * 100

= 40% <===== Maki's increase

4 0

3 years ago

Would it be 6x-3 or 6x^2-3? Composite function

dangina [55]

g(x) = 3x

g(x) = 3( x )

g( f(x) ) = 3( f(x) ) ... replace every x with f(x)

g( f(x) ) = 3( 2x-1 ) .... plug in f(x) = 2x-1

g( f(x) ) = 3( 2x) + 3( -1 ) ... distribute

g( f(x) ) = 6x - 3

You are correct in saying D is the answer

6 0

3 years ago

Need help z-8=3y-x.

Agata [3.3K]

What are you trying to solve for?

3 0

3 years ago

Read 2 more answers

How many pounds are there in 2 and 3 over 4 tons? (1 ton = 2000 pounds)

tankabanditka [31]

4000 pounds, 6000 pound, and 8000 pound is that what you need you question is typed funny

3 0

3 years ago

Read 2 more answers

Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and

Valentin [98]

So we have a set of integers,

$X=\{15,20,25,25,27,28,30,34\}$

And we need to compute some stats.

First the range,

The range of data set is difference between the maximum and the minimum of the data set.

So the minimum is 15 and maximum is 34 therefore the range is 34 - 15 = 19.

Second the interquartile range,

The interquartile range of data set is the difference of the first and third quartiles.

First quartile is the value separating the lower quarter and higher three - quarters of the set. The first quartile is computed by taking median of the lower half of the sorted set. This is 15, 20, 25, 25 and it's median is 22.5

Third quartile is therefore the median of 27, 28, 30, 34 which is 29.

Next up, variance.

The variance of set measures how much data is spread out. For data set $x_1,\dots, x_n$ with an average $a$ ,

$\mathsf{var}(X)=\Sigma_{i=1}^{n}\dfrac{(x_i-a)^2}{n-1}$

So first compute the average value which is actually a mean,

$a=\dfrac{1}{2}\Sigma_{i=1}^{n}a_i$

The sum $\Sigma_{i=1}^{n}a_i$ of numbers in set is 204.

Divide this by number of elements in the set (8).

$a=\dfrac{204}{8}=25.5$

Then compute the variance,

$\mathsf{var}(X)=\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}\approx\boxed{34.57}$

And finally standard deviation,

Since have computed variance the standard deviation is nothing too hard. It's defined as a square root of variance,

$\mathsf{sde}(X)=\sqrt{\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}}=\sqrt{34.57}\approx\boxed{5.88}$

Hope this helps.

r3t40

6 0

3 years ago