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4 years ago

I just realized I had a back side. May someone help me with these as well! Thank you so so much if you do!

Mathematics

1 answer:

SVETLANKA909090 [29]4 years ago

8 0

Answer:

D, C, D, C, B, B, C, A, D.

I guess that's it. Sorry if it's not all correct!

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Given AC-3, 1), B(1, 4) and C(4, 0):

Taya2010 [7]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Find the value of each variable.

insens350 [35]

Step-by-step explanation:

11)

x= 5

${y}^{2} = 2 \times {5}^{2} \\ {y}^{2} = 50 \\ y = 5 \sqrt{2}$

12)

$\tan(30 ) = \frac{9}{y} \\ y = \frac{9}{ \tan(30) } = 9 \sqrt{3} \\ {x}^{2} = {9}^{2} + {(9 \sqrt{3} )}^{2} \\ {x}^{2} = 324 \\ x = 18$

13)

$\sin(60) = \frac{x}{22} \\ x = 11 \sqrt{3} \\ \cos(60) = \frac{y}{22} \\ y = 11$

14)

${16}^{2} = {x}^{2} + {y}^{2} \\ x = y \\ {16}^{2} = 2 {x}^{2} \\ x = 8 \sqrt{2} \\ y = 8 \sqrt{2}$

15)

$\tan(30) = \frac{x}{42} \\ x = 14 \sqrt{3} \\ \cos(30) = \frac{42}{y} \\ y = \frac{42}{ \cos(30) } \\ y = 28 \sqrt{3}$

16)

${(19 \sqrt{2}) }^{2} = {x}^{2} + {y}^{2} \\ x = y \\ 722 = 2 {x}^{2} \\ {x}^{2} = 361 \\ x = 19 \\ y = 19$

4 0

3 years ago

Can the mean value theorum be applied to the function f(x)=1/x^2 on the interval [-2, 1]? Explain.

Temka [501]

Answer:

No, it can not be applied.

Step-by-step explanation:

f(x) = 1/x²

f(x) is a polynomial that is not continuous

As,

f(x) = 1/0 is undefines

Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)

Derivative of this function

f'(x) = (1)x^-2

= -2x^(-2-1)

= -2x^(-3)

= -2/x³

f'(0) = -2/0 is undefined

Thus, mean value theorem can not be applied.

7 0

4 years ago

Bianca can run 5 miles in 41 minutes. Assuming she runs at a constant rate, write the linear equation that represents the situat

ale4655 [162]

Answer:

y=5/41x

Step-by-step explanation:

Alright, so we can get imagine two points. Imagine that the y axis is miles and the x axis is minutes. When bianca runs 0 miles, she would have run for 0 minutes, and we know that when Bianca runs 5 miles, she would have run for 41 minutes.

We can use slope formula using the change in y over change in x

$(y1 -y2)/(x1-x2)\\$

So substituting values, we would get (5-0)/(41-0) or 5/41

slope is the letter m in the formula y=mx+b

so our equation would be $y=\frac{5}{41}x+b$ , b being the y intercept, which would be 0 as you cant run anything when no time has passed

Knowing all of this. the final equation is

$y=\frac{5}{41}x$

6 0

3 years ago

Write a story about temperatures that this expression could represent: 27+(-11)

Lemur [1.5K]

Outside it was 27 degrees. 5 hours later the temperature dropped to 11 degrees

8 0

3 years ago