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3 years ago

Please help meeeeeeeeeeeeeee

Mathematics

2 answers:

galina1969 [7]3 years ago

7 0

Together they scored:
(3x+2)+(300-2x)=347
x+302=347
x=45
Substituting x:
3*45+2=135+2=137
300-2*45=300-90=210
So Makayla scored a total of 210 points

lions [1.4K]3 years ago

4 0

She scored a total of 210 points

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FACTOR.... x^2 + 10× - 2400 = 0

Vikki [24]

Answer:

x= -5 + 5 $\sqrt{97}$ , x= -5 - 5 $\sqrt{97}$

Step-by-step explanation:

Since this quadratic is set to zero, we can use the quadratic formula to solve this.

x^2 + 10x - 2400 = 0

Quadractic formula = x= -b +- $\sqrt{b^2 - 4ac}$ /2a

For this equation:

a= 1, b=10, c=-2400

Plug these numbers into the equation and solve.

x= -10 +- $\sqrt{10^2 - 4(1)(-2400}$ )/2(1)

x= -10 +- $\sqrt{100 + 9,600}$ /2

x= -10 +- $\sqrt{9,700}$ /2

x= -10 +- $\sqrt{2^2 * 5^2 * 97}$ /2

x= -10 +- 5 * 2 $\sqrt{97}$ /2

x= -10 +- 10 $\sqrt{97}$ / 2

Divide by 2.

x= -5 +- 5 $\sqrt{97}$

Answer:

x= -5 + 5 $\sqrt{97}$ or x= -5 - 5 $\sqrt{97}$

5 0

3 years ago

What is the solution to the system of equations

FromTheMoon [43]

Answer:

(0,3)

Step-by-step explanation:

solve for 2y

-X-2y= -6

2y=6+2x

substitute the given value of 2y into the equation -x-2y=-6

-x-(6+3x)= -6

solve for x

x=0

substitute the given value of X into the equation 2y=6+3x

2y=6+3×0

solve for y

y=3

the solution is (0,3)

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2 years ago

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

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3 years ago

What are three equivalent ratios for 5/45

Burka [1]

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