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dexar [7]
2 years ago
11

Drag each tile to the correct location. Each tile can be used more than once, but not all tiles will be used.

Mathematics
1 answer:
AysviL [449]2 years ago
6 0

Answer:

y=770-55x --- given

y - 770 = 770 - 55x - 770 ----subtraction property of equality

y = -55x + 770 ---Simplification

y-770/-55 = -55x/-55 --- Division property of equality

-y-770/55=x---Simplification

Step-by-step explanation:

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The area of a rectangle is 8w + 18 square feet. The length of the rectangle is 2 feet. Use factoring to write an expression to r
qwelly [4]

Answer:

4w + 9

Step-by-step explanation:

Area of rectangle = length x width (or base x height, depending on how you look at it).

It is given to you that:

Area = 8w + 18

Length = 2

Let: width = x

Plug in the corresponding terms with the corresponding words:

8w + 18 = 2x

Isolate the variable, x. Divide 2 from both sides of the equation:

(8w + 18)/2 = (2x)/2

x = (8w + 18)/2

w = (8w)/2 + (18)/2

w = 4w + 9

4w + 9 is the expression that represents the width of the rectangle.

~

6 0
2 years ago
What is the volume of a rectangle prism that is 1 1/2 inches by 2 1/4 inches by 4 inches?
Reptile [31]

Answer:

13.5 inches

Step-by-step explanation:

11.5 x 2.25 x 4

I could be wrong

7 0
2 years ago
Read 2 more answers
Colin drove 45 minutes to the airport. He arrived 90 minutes before his flight departed, and then he spent 70 minutes in the air
shtirl [24]
The answer is 50 minutes bro
8 0
3 years ago
Let R be the region in the first quadrant of the​ xy-plane bounded by the hyperbolas xyequals​1, xyequals9​, and the lines yequa
Tema [17]

Answer:

The area can be written as

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = 0.2274

And the value of it is approximately 1.8117

Step-by-step explanation:

x = u/v

y = uv

Lets analyze the lines bordering R replacing x and y by their respective expressions with u and v.

  • x*y = u/v * uv = u², therefore, x*y = 1 when u² = 1. Also x*y = 9 if and only if u² = 9
  • x=y only if u/v = uv, And that only holds if u = 0 or 1/v = v, and 1/v = v if and only if v² = 1. Similarly y = 4x if and only if 4u/v = uv if and only if v² = 4

Therefore, u² should range between 1 and 9 and v² ranges between 1 and 4. This means that u is between 1 and 3 and v is between 1 and 2 (we are not taking negative values).

Lets compute the partial derivates of x and y over u and v

x_u = 1/v

x_v = u*ln(v)

y_u = v

y_v = u

Therefore, the Jacobian matrix is

\left[\begin{array}{ccc}\frac{1}{v}&u \, ln(v)\\v&u\end{array}\right]

and its determinant is u/v - uv * ln(v) = u * (1/v - v ln(v))

In order to compute the integral, we can find primitives for u and (1/v-v ln(v)) (which can be separated in 1/v and -vln(v) ). For u it is u²/2. For 1/v it is ln(v), and for -vln(v) , we can solve it by using integration by parts:

\int -v \, ln(v) \, dv = - (\frac{v^2 \, ln(v)}{2} - \int \frac{v^2}{2v} \, dv) = \frac{v^2}{4} - \frac{v^2 \, ln(v)}{2}

Therefore,

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = \int\limits_1^2 (\frac{1}{v} - v \, ln(v) ) (\frac{u^2}{2}\, |_{u=1}^{u=3}) \, dv= \\4* \int\limits_1^2 (\frac{1}{v} - v\,ln(v)) \, dv = 4*(ln(v) + \frac{v^2}{4} - \frac{v^2\,ln(v)}{2} \, |_{v=1}^{v=2}) = 0.2274

4 0
3 years ago
What is r- 11 /3 = -7
Oksanka [162]
Wouldn't r = -10?
because you'd multiply -7 by 3, to get rid of the division.
then you'd add 11.
3 0
3 years ago
Read 2 more answers
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