Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

Answer:

D

Step-by-step explanation: i got that ? and i got it right actually not kidding!

Answer 2

Answer:  A & B are the same answer --> 96, max

Step-by-step explanation:

Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:

• If m > n, then there is no H.A.
• If m = n, then y = coefficient of numerator ÷ coefficient of denominator
• If m < n, then y = 0

In the given problem, m = 1 and n = 1 so the H.A. is:

$y=\dfrac{60}{0.625}\quad \rightarrow \quad y=96$

This is the maximum number of moose that the forest can sustain at one time.