PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
2 answers:
Answer: A & B are the same answer --> 96, max
<u>Step-by-step explanation:</u>
Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:
- If m > n, then there is no H.A.
- If m = n, then y = coefficient of numerator ÷ coefficient of denominator
- If m < n, then y = 0
In the given problem, m = 1 and n = 1 so the H.A. is:
This is the maximum number of moose that the forest can sustain at one time.
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Answer:
Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form , where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario ,
and
. Upon substituting these values in object's height function, we will get:
Therefore, the function for the height of the arrow would be .