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3 years ago

40 kg to 32 kg as a fraction

Mathematics

2 answers:

user100 [1]3 years ago

8 0

hope it helps you

keep learning more

frez [133]3 years ago

3 0

Answer:

18/25...............

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46 out of 200 dogs are short haired breeds. What percent of dogs are not short haired breeds

Ivahew [28]

Hi!

46 out of 200 are short haired, which means that 200 - 46 = 154 out of 200 are not short haired. In percentages, that is:

154/200 = 77/100 = 77%

Hope this helps!

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3 years ago

What are the variables for question 5, problem a, I don't quite understand.

valentinak56 [21]

One variable is the amount of time it takes her to make a plate. The other variable is the amount of time it takes her to make a cup.

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3 years ago

Find the inverse of: f(x)=3x-8

Crazy boy [7]

The answer is f^-1(x)=8/3+x/3

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3 years ago

Lisa Purchased almonds for $3.50 per pound. She spent a total of $24.50. how many pounds of almond did she purchase?

Margaret [11]

Answer:

7 pounds of almond

Step-by-step explanation:

It is $3.50 per pound.

If she spent a total of $24.50, just divide 24.50 by 3.50

$\frac{24.50}{3.50}$ = 7

We can verify this by multiplying 3.50 by 7 which gives us 24.50

5 0

2 years ago

Read 2 more answers

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

the answer Part a) is

the speed is equal to $3.5\frac{m}{sec}$

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

the answer Part b) is

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

the answer Part c) is

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

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3 years ago

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