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Nina [5.8K]
3 years ago
15

The volume of a cube is 1000cm^3. what is the length of an edge

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

10

Step-by-step explanation:

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The population of at a town has grown 2% each year. In 1998, the population of the town was about 10,000 people. What was the po
Nuetrik [128]

Answer:

10200

Step-by-step explanation:

This is an example of a compound interest. The equation for this problem is 10000*(1+2/100)^n. The n is the year as 1999 is 1 year away from 1998, you just replace n with 1 and you have a simple equation.

7 0
3 years ago
Select all the correct answers.
MA_775_DIABLO [31]

Answer:

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4 0
3 years ago
A triangle has sides with lengths of 43 millimeters, 52 millimeters, and 65 millimeters. Is it a right triangle
Mrrafil [7]
Use pythagora's theorem to test if it is a right triangle

c^2 = a^2 + b^2
65^2 = 52^2 + 43^2
4225 = 2704 + 1849
4225 =/= 4553
therefore it is not a right triangle as it does not comply to pythagora's theorem
7 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
I just need help in one more ?
Fed [463]
M∠P = 12°
m∠Q = 90°   [A tangent line to a circle is perpendicular to the radius drawn to the tangent point]

m∠O = 90 - 12 = 78°

Answer: x=78°
8 0
3 years ago
Read 2 more answers
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