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Semenov [28]
3 years ago
13

Simplify (This is a fraction) : 9^6 over 9^7

Mathematics
1 answer:
trapecia [35]3 years ago
3 0

when 2 exponents of like bases are divided, you can subtract the exponents

1. \frac{9^6}{9^7} = \frac{1}{9}

2. \frac{9^2}{9^7} = \frac{1}{9^5}

3. 9^5 = 9^5

4. \frac{1}{9^9} = \frac{1}{9^9}

5. negative exponents mean move to opposite sides, so

\frac{1}{9^{-5}} = \frac{9^5}{1}=9^5

6. \frac{1}{9^5} = \frac{1}{9^5}

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Please help the question is on the picture!
Sloan [31]

Answer:

I think it is 0 not sure about it

3 0
3 years ago
0.546 = 0.4 + ? + 0.006<br> Please Explain the Answer to me!
nadya68 [22]

Answer:  ? = 0.14

Step-by-step explanation:

So you need to find the value that fits the question mark. This means you have to get it by itself.

To start you subtract 0.4 from 0.546, which equals .146. Then you subtract 0.006 from 0.146 to get 0.14

What it looks like mathematically :

0.546 = 0.4 + ? + 0.006  

0.146= ? + 0.006  

0.14=?

Hopes this helps :)

5 0
3 years ago
A company that offers tubing trips down a river rents tubes for a person to use for $20 and “cooler” tubes to carry food and wat
aivan3 [116]

The group rent 11 river rent tubes and 4 cooler tubes.

Step-by-step explanation:

Rent for river rent tube = $20

Rent for cooler tubes = $12.50

Total spent = $270

Total tubes rented = 15

Let,

x be the number of river rent tube.

y be the number of cooler tubes.

According to given statement;

x+y=15    Eqn 1

20x+12.50y=270    Eqn 2

Multiplying Eqn 1 by 20

20(x+y=15)\\20x+20y=300\ \ \ Eqn\ 3

Subtracting Eqn 2 from Eqn 3

(20x+20y)-(20x+12.50y)=300-270\\20x+20y-20x-12.50y=30\\7.50y=30

Dividing both sides by 7.5

\frac{7.5y}{7.5}=\frac{30}{7.5}\\y=4

Putting y=4 in Eqn 1

x+4=15\\x=15-4\\x=11

The group rent 11 river rent tubes and 4 cooler tubes.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/8520610
  • brainly.com/question/846474

#LearnwithBrainly

6 0
3 years ago
50 cases in 44 minutes equals how many cases in 60 minutes
Blizzard [7]
To solve this, set up a proportion, crossmultiply, and solve for x. 

Let x = the unknown amount of cases in 60 minutes.

\frac{50}{44} = \frac{x}{60}
44x = 50(60)
44x = 3000

Divide both sides by 44 to isolate variable x
x = 3000 / 44
x ≈ 68.1818 (the 18s repeat forever)

Rounding to the closest case and assuming the rate stays constant, you would get approximately 68 cases in 60 minutes. If you need not round to the nearest case, you would get approximately 68.18 cases in 60 minutes. 
4 0
3 years ago
Find an equation of the plane. the plane through the point (3, 0, 7) and perpendicular to the line x = 5t, y = 2 − t, z = 8 + 4t
Gnom [1K]
Let's write the parametric line

(x,y,z) = (0,2,8) + t(5,-1,4)

(5,-1,4) is called the direction vector of the line.   It's normal to the plane

5x - y + 4z = constant

We get the constant by substituting the point (3,0,7),

5x - y +4z = 5(3) - 0 + 4(7) = 43

5x - y +4z = 43

4 0
3 years ago
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