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2 years ago

Translate the sentence into an equation or formula.

Mathematics

1 answer:

inn [45]2 years ago

6 0

4 times the sum of f and g: 4(f+g)
6 times g: 6g

So equation : 4(f+g) = 6g

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Find two possible factors for the estimated product 1600

TEA [102]

Two factors that give a product of 1600 can be 80 × 20

4 0

3 years ago

I SEE YALL LOOKING BUT NOT HELPING PLEASE SOMEONE

bezimeni [28]

Answer:

the pitcure isnt clear.

8 0

3 years ago

How do i solve for x

Dafna11 [192]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! so im pretty sure its 20

5 0

2 years ago

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= <u>0.1773</u>

3 0

3 years ago

What are the values of the variables in the triangle below? If your answer is not an integer, leave it in simplest radical form.

castortr0y [4]

Answer:

Step-by-step explanation:

<u>To find x we use cosine</u>

cos∅ = adjacent / hypotenuse

x is the adjacent

8√3 is the hypotenuse

cos 30 = x / 8√3

x = 8√3 cos 30

<u>To find y we use sine</u>

sin∅ = opposite / hypotenuse

y is the opposite

8√3 is the hypotenuse

sin 30 = y / 8√3

y = 8√3 sin 30

Hope this helps you

5 0

2 years ago