All categories

3 years ago

Barney is eight years older than Nemo. In seven years the sum of their ages will be 46. How old is Barney now?.

1 answer:

6 0

Let's represent Nemo's age with an n.

Barney is 8 years older so his age is nemo's plus 8. That is, Barney's age is n + 8

In seven years they will each be the age they are now plus 7. So, Nemo will be n + 7 and Barney will be n + 8 + 7. If the sum of their ages will be 46 we know that when we add these expressions we should get 46, so let's set the sum to 46 and solve for n.

n + 7 + n + 8 + 7 = 46
2n + 22 = 46
2n = 46 - 22
2n = 24
n = 12

That means that Nemo's age is 12.
Since Barney is 8 years older his age is 12 + 8 = 20.

To check our work we see that in 7 years Nemo will be 12 + 7 = 19 and Barney will be 20 + 7 = 27. Together that is 19 +27 = 46 as expected.

You might be interested in

fredd [130]

9514 1404 393

Answer:

(b) (-3, -1)

Step-by-step explanation:

Differences between adjacent f(x) values are ...

-31, -13, -1, +5, +5, -1, -13

The function is increasing on intervals where the differences are positive: between (-3, -11) and (-1, -1). That is ...

f(x) is increasing on (-3, -1)

5 0

2 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago

What is the pathorgeon

SCORPION-xisa [38]

Answer:

it is in a term in biology that came into use in the 1800's to show about anything that can produce disease Hope this helps can I get branliest answer?

Step-by-step explanation:

8 0

3 years ago

What are the quotient and remainder when 777 is divided by 21?

DIA [1.3K]

777 divided by 21 = 34 with a remainder of 3

5 0

2 years ago

jack donates $X per month to charity. Ta the end if 10 months, he had 1250 donated in total. How much did he donate each month

AnnZ [28]

Answer:

He donated $125 per month.

Step-by-step explanation:

$1250 divided by 10 months to figure out how much he payed each month.

4 0

3 years ago