Answer:
1.4 times as high
Step-by-step explanation:
Now here we have to compare the both final velocities by using the formula independent of time. As we know,
2aS = V(f)2 - V(i)2
Both balls are dropped from certain height, so V(i) = 0 m/s for both balls
So, 2aS = V(f)2 for both balls.
Now if we compare both velocities
Equation for first ball
2aS(1) = V(1)2
Equation for second ball
2aS(2) = V(2)2
Comparing both equations
2aS(1)/2aS(2) = V(1)2/V(2)2
as we now S(1) = 5m and S(2) = 10m, also acceleration a = g, because acceleration due to gravity is acting on the balls. So,
2(9.8) x 5/2(9.8) x 10 = V(1)2/V(2)2
after simplifying,
1/2 = V(1)2/V(2)2
V(2)^2 = 2V(1)^2
By taking square root on both sides,
V(2) = 1.4V(1)