Answer:
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Step-by-step explanation:
The null hypothesis is:

The alternate hypotesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.
This means that 
Assume the population standard deviation is 6.2 weeks.
This means that 
Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
We have to find the pvalue of Z, looking at the z-table, when
. It if is lower than 0.05, it provides evidence.



has a pvalue of 0.0113 < 0.05.
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Your list of numbers needs a bit of clarification.
You wrote: <span>.9,1.1,.10 38 and .10299
I have to make some assumptions here, and to ask whether you meant the following:
</span><span>.9, 1.1, .1038 and .10299
If so, now's the time to look for the smallest and the largest of these numbers. The smallest is 0.10299:
smallest
</span>
0.10299
<span>0.1038
0.9
1.1
</span>.9, 1.1, .1038 and .10299
If my list disagrees with yours, please ensure that you have copied down these four numbers correctly and then try again (on your own) to order them correctly from smallest to largest.
Answer: the answer is $456 and that is correct
Step-by-step explanation:
152×3= $456