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3 years ago

What is the solution to 7x + 6y if y = 10 and x = 2?

Mathematics

2 answers:

Fittoniya [83]3 years ago

5 0

Hi there! Hopefully this helps!

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<h2>Answer: 74</h2>

First we need to evaluate the variables into the expression.

7x + 6y = 7(2) + 6(10).

6 x 10 = 60

7 x 2 = 14.

60 + 14 = 74

lapo4ka [179]3 years ago

4 0

Answer: First we will substitute the numbers in place of the variables in the equation, and then we will use order of operations to solve.

7x + 6y would be equal to:

7(2) + 6(10)

Now we will perform the multiplication:

7 * 2 = 14

6 * 10 = 60

The equation now looks like:

14 + 60

This is equal to 74. Your answer is therefore 74.

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The three multiples are 36 are

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Answer: 1) Both gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

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Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.

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4 years ago

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Answer:

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This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

$p_1=X_1/n_1=188/244=0.77049$

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

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$p_d=p_1-p_2=0.77049-0.79757=-0.02708$

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The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(t$

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

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