Answer:
2m + 22
Step-by-step explanation:
Use the distributive property.
2(m + 11)
2 x m = 2m
2 x 11 = 22
Therefore, 2m + 22
Answer:
A. 12
Step-by-step explanation:
use pemdas
4^4=16
20+8=28
28-16=12
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
Answer:
16 : 28
Step-by-step explanation:
If 12 out of the 28 pupils are female, we can calculate the number of males by subtracting the number of females from the total number of pupils.
28 - 12 = 16
So, there are 16 males in the class. Now, we know that the ratio of males : total is 16 : 28.
I hope this helps! Have a lovely day!! :)
(brainliest is much appreciated!!)
7x + 3 is the final answer
