What is the answer to 81.56 + n

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29). Round your answer to at least three deci

ss7ja [257]

Answer:

a) 0.76197086

b) -1.73406361

Step-by-step explanation:

a)

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29)

P(-1.29 < t < 1.29) would be the area under the t distribution curve with 7 degrees of freedom between -1.29 and 1.29, that is in the interval (-1.29, 1.29).

This can be done the old style by looking up in a table or by using the technology with a spreadsheet.

In Excel, the function TDIST(x,n,2) with x>0 gives the area outside the interval (-x, x) of the t distribution with n degrees of freedom.

So TDIST(1.29,7,2) gives the area outside (-1.29, 1.29).

If we subtract this value from 1 we get the desired result

Hence

P(-1.29 < t < 1.29) = 1 - TDIST(1.29,7,2) = 1 - 0.23802914 = 0.76197086

In OpenOffice Calc, the function is the same replacing “,” with “;”

That is

P(-1.29 < t < 1.29) = 1 - TDIST(1.29;7;2) = 0.76197086

b)

Consider a t distribution with 18 degrees of freedom. Find the value of c such that P(t≤ c) = 0.05

We are looking for a point c such that the area of the t distribution with 18 degrees of freedom to the left of c is 0.05

In Excel, the inverse function of TDIST is TINV.

TINV(p*2,n) with p>0 gives the point c such that the area of the t distribution with n degrees of freedom to the right of c is p.

Since <em>the t distribution is symmetric with respect to 0</em>, -c would be a point such that the area to the left of -c is p.

So we want to compute in Excel

-TINV(0.05*2,18) = -1.73406361

In OpenOffice Calc

-TINV(0.05*2;18) = -1.73406361

3 0

2 years ago

What is the sum of the first five terms of a geometric series with A1 equals 20 and R equals 1/4

sweet-ann [11.9K]

Sum = 20(1-(1/4)^5) / (1-1/4) = 26.64

6 0

2 years ago

What is limit of (x cubed 3 x squared 4 x minus 12) as x approaches negative 3? –78 –24 30 54

Sergio039 [100]

The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

$x^3 + 3x^2 + 4x - 12$

As x approaches -3.

The limit expression becomes

$\lim_{x \to -3} x^3 + 3x^2 + 4x - 12$

Substitute -3 for x in the expression

$\lim_{x \to -3} (-3)^3 + 3(-3)^2 - 4*3 - 12$

Evaluate the expression

$\lim_{x \to -3} -24$

Hence, the limit of the expression as x approaches -3 is -24

Read more about limit expressions at:

brainly.com/question/16176002

#SPJ4

7 0

1 year ago

What is the sum of all the integers between the square root of 19 and the square root of 77?

Artist 52 [7]

Since we are only dealing with integers, we do not need to worry about decimals. Therefore, finding the exact values of sqrt(19) and sqrt(77) is not important. We can just estimate.

19 is between 16 and 25 (which are 4^2 and 5^2), so the square root of 18 is some number between 4 and 5.

77 is between 64 and 81 (which are 8^2 and 9^2), so the square root of 77 is some number between 8 and 9.

So the integers (whole numbers) that are between our two sqaure roots are 5, 6, 7, and 8.

Add them up and we have our answer.

5+6+7+8 = 26

4 0

3 years ago

PQ and QR are two sides of a regular 12-sided polygon. PR is the diagonal of the polygon.

skelet666 [1.2K]

The size of angle PRQ is 15°

Step-by-step explanation:

In any regular polygon of n-sided

All sides are equal in length
All angles are equal in measure
The measure of each interior angle is $\frac{(n-2)*180}{n}$
The measure of each exterior angle is $\frac{360}{n}$
The sum of the measures of the interior and exterior angle at the same vertex is 180°

∵ PQ and QR are two sides of a regular 12-sided polygon

∴ PQ = QR

∵ PR is a diagonal

∴ ∠PQR is an interior angle of the polygon

- By using the rule of the interior angle above

∵ n = 12

∴ m∠PQR = $\frac{(12-2)*180}{12}$

∴ m∠PQR = 150°

In Δ PQR

∵ PQ = QR ⇒ sides in a regular polygon

- Δ PQR is an isosceles Δ

∴ m∠PRQ = m∠RPQ ⇒ base angles of an isosceles Δ

The sum of the measures of the interior angles of a triangle is 180°

∵ m∠PQR + m∠PRQ + m∠RPQ = 180°

∴ 150 + m∠PRQ + m∠RPQ = 180°

- Subtract 150 from both sides

∴ m∠PRQ + m∠RPQ = 30

∵ m∠PRQ = m∠RPQ

- Divide their sum by 2 to find the measure of each one

∴ m∠PRQ = m∠RPQ = 30 ÷ 2 = 15°

∴ m∠PRQ = 15°

The size of angle PRQ is 15°

Learn more:

You can learn more about the triangles in brainly.com/question/3945600

#LearnwithBrainly

4 0

2 years ago

What is the answer to 81.56 + n - 2.55