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2 years ago

List THE numbers in order from least no greatest-65,34,7,-13,55,62,-7

1 answer:

ivann1987 [24]2 years ago

7 0

-65, -13, -7, 7, 34, 55, 62.
Here’s your answer^
Least to greatest

Always negative will be least and positive will be the greatest always.

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Circle A has a diameter of 9 inches, a circumference of 28.26 inches, and an area of 63.585 square inches. The diameter of circl

torisob [31]

Please note that pi has just one value. The only difference stems from round-off error when you don't use all of the digits following "3.14159 ... " to represent the value of pi. The formula for circumference is C = 2 pi r, or C = pi d,
where r=radius and d=diameter.

Circle A: Diameter 9 inches and Circumference of 28.26 inches

If the diameter is 9 inches, then C = 28.26 inches = pi (9 inches). Divide 28.26 inches by 9 inches. Note that you MUST round off the ratio (pi) that you obtain, since 28.26 has 4 significant figures and 9 has just one.

28.26
------- = 3.14, but because 9 has just one significant figure, you must round
9 this 3.14 to just 3.

6 0

3 years ago

The probability that a can of paint contains contamination is 3.23%, and the probability of a mixing error is 2.4%. The probabil

stich3 [128]

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

$P(C \cap M)=1.03\%$

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. $P(C \cup M)$

In probability theory:

$P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%$

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

3 0

3 years ago

0.5a − 0.3 = 5 (solve for a)

Alla [95]

0.5a - 0.3 = 5

Add 0.3 to both sides:

0.5a = 5.3

Divide both sides by 0.5:

a = 10.6

3 0

3 years ago

Read 2 more answers

Expression using the numbers 7,5,6,3 to equal 75

Inga [223]

(7 + 5) x 6 + 3. (7 + 5 = 12, 12 x 6 = 72, 72 + 3 = 75.)

5 0

3 years ago

2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe

k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

$N=(25+60)+(40+60) - 60\\N= 125$

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

$P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%$

3 0

2 years ago