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xz_007 [3.2K]
3 years ago
12

List THE numbers in order from least no greatest-65,34,7,-13,55,62,-7

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0
-65, -13, -7, 7, 34, 55, 62.
Here’s your answer^
Least to greatest

Always negative will be least and positive will be the greatest always.
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If this sample is representative of the student population of 360 students, about how many students in the school joined three c
kirill115 [55]

Answer:

For 1 club it is 120 students

Step-by-step explanation:

360/3=120

3 0
3 years ago
Any help would be appreciated! <br> 7/9+ 8/9 as a mixed number
katovenus [111]

Answer:

15/9 :))

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Read 2 more answers
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
The length of a rectangle is 5/6 inches and the width of the rectangle is 2/15 inches. What is the area of the rectangle (write
Snowcat [4.5K]
1/9


Mark brainliest please


Hope this helps you
3 0
3 years ago
Simplify (-3x^2)^2 show work
Feliz [49]

Answer: 9x^4

Using the rules of exponents multiply the -3 times the -3 which equals 9 canceling out the negatives. Then you have that other ^2 but you also had the other one so you still have to keep it which equals that ^4.

6 0
3 years ago
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