Ask question

Ask question

All categories

3 years ago

12

How do I find the reciprocal of the fractions 2/3 and 8/3

2 answers:

Mice21 [21]3 years ago

5 0

2/3 reciprocal is 3/2, & 8/3 reciprocal is 3/8. The numbers are just filled to find their reciprocal!

dexar [7]3 years ago

5 0

To find the reciprocal you just flip the fraction

You might be interested in

(3x + 2y = 7<br> (7x-2y = 3

sineoko [7]

Answer for the equation by elimination

8 0

1 year ago

Andrew is elder to Brian by 2 years. Andrew's father Frank is twiceas old as Andrew, and Brian is twice as old as his sister Sar

babunello [35]

Let "x" represent the age of Brian.

Andrew is elder than Brian by 2 years, we can symbolize his age as "x+2"

Frank is twice as old as Andrew, we can symbolize his age as "2(x+2)"

Sarah has half the age of Brian's, we can symbolize her age as "x/2"

Frank ans Sarah's ages differ by 40 years, we can symbolize this as:

$2(x+2)-\frac{x}{2}=40$

Solve the term is parenthesis

$\begin{gathered} 2x+4-\frac{1}{2}x=40 \\ 2x-\frac{1}{2}x+4=40 \\ \frac{3}{2}x=40-4 \\ \frac{3}{2}x=36 \\ x=24 \end{gathered}$

x=24 years

Andrew's age is

$x+2=24+2=26$

Andrew is 26 years old

3 0

1 year ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

2 years ago

Read 2 more answers

A thermometer shows a temperature of Negative 20 and three-fourths degrees. A chemist recorded this temperature in her notebook

fredd [130]

Answer:

The answer is C.

Step-by-step explanation:

3/4 is equal to 0.75. If you combine 0.75 with -20, then it is 20.75.

4 0

3 years ago

Read 2 more answers

Can you help please no links or point stealing or I will report

avanturin [10]

Answer: first one 5.55

Step-by-step explanation:

-4x+8=42

-4x+8-8=42-8

-4x=34

-4x=34

-4x/-4=34/-4

x= - 17/3

7 0

2 years ago

Read 2 more answers