The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Step-by-step explanation:
You can plot linear graph using two point (x1,y1) and (x2,y2), where x1, y1, x2 and y2 are real numbers.
or
using slope intercept form y = mx + b, where m is the slope and b is y-intercept.
Answer:
-6 ≤ x ≤ 16
Step-by-step explanation:
First, apply absolute value rule:
x - 5 ≤ 11 and x - 5 ≥ -11
Then, we add 5 on both sides with both inequalities:
x ≤ 16 and x ≥ -6
Finally, combine the inequalities:
-6 ≤ x ≤ 16
And we're done ^^
The answer choices ? did u forgot that
Answer:
VOLUME OF THE CYLINDER=πr²h
=3.14×4²×9
=3.14×16×9
=452.16 mm³
