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larisa86 [58]
3 years ago
7

A dietician is planning a snack package of fruit and nuts. Each ounce of fruit will supply 1 unit of​ protein, 2 units of​ carbo

hydrates, and 1 unit of fat. Each ounce of nuts will supply 1 unit of​ protein, 1 unit of​ carbohydrates, and 1 unit of fat. Every package must provide at least 7 units of​ protein, at least 11 units of​ carbohydrates, and no more than 10 units of fat. Let x equal the ounces of fruit and y equal the ounces of nuts to be used in each package.
a. Write a system of inequalities to express the conditions of the problem.
b. Graph the feasible region of the system.
a. Fill in the chart.
Fruit
Nuts
Requirements per package
Protein
nothing ​unit(s) per ounce
nothing ​unit(s) per ounce
At least
nothing ​unit(s)
Carbohydrates
nothing ​unit(s) per ounce
nothing ​unit(s) per ounce
At least
nothing ​unit(s)
Fat
nothing ​unit(s) per ounce
nothing ​unit(s) per ounce
No more than
nothing ​unit(s)

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

Each ounce of fruit will supply

  • 1 unit of​ protein,
  • 2 units of​ carbohydrates,
  • 1 unit of fat.

Each ounce of nuts will supply

  • 1 unit of​ protein,
  • 1 unit of​ carbohydrates,
  • 1 unit of fat.

Let x equal the ounces of fruit and y equal the ounces of nuts to be used in each package.

Then x ounces of fruit will supply

  • x units of​ protein,
  • 2x units of​ carbohydrates,
  • x units of fat

and y ounces of nuts will supply

  • y units of​ protein,
  • y units of​ carbohydrates,
  • y units of fat.

Every package must provide

  • at least 7 units of​ protein, then x+y≥7,
  • at least 11 units of​ carbohydrates, then 2x+y≥11,
  • and no more than 10 units of fat, then x+y≤10.

A. You get the system of three inequalities

\left\{\begin{array}{l}x+y\ge 7\\ 2x+y\ge 11\\x+y\le 10\end{array}\right.

B. See attached diagram

\begin{array}{cccc}&\text{Protein}&\text{Carbohydrates}&\text{Fat}\\\text{Fruit}&x&2x&x\\\text{Nuts}&y&y&y\\&\text{at least 7}&\text{at least 11}&\text{no more than 10}\end{array}

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 P(X = 8) =  0.0037

b

 P(X <  5) =  0.805

c

 P(X > 6) =  0.0206

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is p = 0.267

Generally data collected from this study follows  binomial  distribution because the number of trials is  finite , there are only two outcomes, (covering  , and  not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable  X we have that  

   X \ \ \~ \ \ { B ( p , n )}

The probability distribution function for binomial  distribution is  

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Considering question a

Generally the  the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when​ sneezing is mathematically represented as

     P(X = 8) =  ^{12} C_8 *  (0.267)^8 *  (1- 0.267)^{12-8}

Here C denotes  combination

So

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    P(X = 8) =  0.0037

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when​ sneezing is mathematically represented as

     P(X <  5 ) =[P(X = 0 ) + \cdots + P(X = 4)]

=>   P(X <  5 ) =[ ^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0} + \cdots +  ^{12} C_4 *  (0.267)^4 *  (1- 0.267)^{12-4} ]

=> P(X <  5 )  =  0.02406 +  0.10516 + 0.21067 + 0.25580 + 0.20964

=>  P(X <  5) =  0.805

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Generally the probability that fewer than half(6) covered their mouth when​ sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

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=>    P(X > 6) =  0.0206

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