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Alecsey [184]
3 years ago
6

Can someone help me ?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

A) 1/6

Step-by-step explanation:

Common Ration means you need to divide second term/first term, third term/2nd term

12/72 = 1/6

2/6 = 1/6

Therefore the common ratio is 1/6

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Calculate the average rate of change for the given graph from x = –2 to x = 0 and select the correct answer below.
Gwar [14]
\frac{6-0}{0+2} = \frac{6}{2} =
3

The equation you use to find the average rate of change, or slope, is \frac{y_{2}-y_{1}}{x_{2}-y_{1}}
7 0
3 years ago
Read 2 more answers
What is the square route of five
CaHeK987 [17]

<u><em>Answer: =2.23</em></u>

Step-by-step explanation:

Square root like this: √

5=2.23

You can also round up to the nearest hundredths and it's going to be stay. If the digit is 5 or more it's going to round up to the nearest tenths, hundredths, and thousandths.

Hope this helps!

Thank you!

Have a great day!


6 0
3 years ago
Read 2 more answers
Angle 4 above has a measurement of 160 degrees. Angle 1 has a label
Elena-2011 [213]

Answer: A

Step-by-step explanation:

5 0
2 years ago
At the instant that a cake is removed from the oven, the temperature of the cake is 350°F. After 10 minutes, the cake's temperat
BARSIC [14]
Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).

This problem can be expressed in a ratio: 
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F

</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes

Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
8 0
3 years ago
PLEASE HELP
notsponge [240]

Answer:

(a)

x cubed is

=x^3=x3

5 times the cube of x is

=5x^3=5x3

4 times x is

=4x=4x

the quotient of 4 times x and 3 is

=\frac{4x}{3}=34x

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}=5x3−34x ..........Answer

(b)

5 times cube of x is

=5x^3=5x3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}=4x5x3 ..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4=5x3−4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}=x5x3−4 ...........Answer

(d)

difference of 5 times x and 4 is

=5x-4=5x−4

so,

the cube of the difference of 5 times x and 4 is is

=(5x-4)^3=(5x−4)3 ............Answer

5 0
2 years ago
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