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madreJ [45]
3 years ago
5

Give the amplitude, vertical and horizontal shift, and period of the function.

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:

Amplitude: 4

Period: 6π

Phase Shift: 0 (0 to the right)

Vertical Shift: 0

Step-by-step explanation:

Use the form

a sin(bx−c)+d

to find the amplitude, period, phase shift, and vertical shift.

Ivanshal [37]3 years ago
4 0
Vertical shift up then down
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I don’t think it would work it you solved for k instead of y. Because you’re solving for y when you do constant of proportionality. i’m not sure if i’m right or not but that’s what i think.
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Answer:

Step-by-step explanation:

okay so if we lay it out...,

f(x)              6-5x                x-9           x³           2x-5            12x+3

f(-3)              21                   12            -27           -11               -33

f(-2)              16                   -11           -8              -9                -21

f(0)                6                   -9             1                -5                 3

f(1)                 1                    -8             1                -3                 15

f(2)               -4                    -7            8               -1                   27

okay so the left side is all the f(x) values. So the numbers in the "()" represents "x". Now you just substitute the numbers in the"()" for the "x"'s on the top margins. so...,

f(-3)= 6-5x            f(-2)= 6-5x                 f(0)=6-5x               f(1)=6-5x        f(2)=6-5x

f(-3)= 6-5(-3)         f(-2)= 6-5(-2)             f(0)=6-5(0)            f(1)=6-5(1)       f(2)=6-5(2)

f(-3)= 6+15            f(-2)= 6+10                 f(0)=6-0                f(1)=6-5          f(2)=6-10

f(-3)= 21                f(-2)= 16                      f(0)=6                   f(1)= 1              f(2)= -4

f(-3)=x-9               f(-2)=x-9                      f(0)=x-9               f(1)=x-9            f(2)=x-9

f(-3)=(-3)-9            f(-2)=(-2)-9                  f(0)=0-9              f(1)=1-9             f(2)=2-9

f(-3)=-12                f(-2)=-11                       f(0)= -9                f(1)= -8            f(2)= -7

f(-3)=x³                 f(-2)=x³                        f(0)=x³                f(1)= x³              f(2)=x³

f(-3)=(-3)³             f(-2)= (-2)³                    f(0)=0³               f(1)=1³                f(2)=2³

f(-3)= -27             f(-2)= -8                        f(0)= 1                f(1)= 1                 f(2)=8

f(-3)= 2x-5           f(-2)= 2x-5                 f(0)= 2x-5            f(1)= 2x-5      f(2)=2x-5

f(-3)=2(-3)-5         f(-2)=2(-2)-5              f(0)= 2(0)-5          f(1)= 2(1)-5     f(2)=2(2)-5

f(-3)= -6-5            f(-2)= -4-5                  f(0)=0-5               f(1)=2-5         f(2)=4-5

f(-3)= -11               f(-2)= -9                      f(0)= -5                f(1)= -3          f(2)= -1

f(-3)=12x+3            f(-2)=12x+3              f(0)=12x+3          f(1)=12x+3     f(2)=12x+3

f(-3)= 12(-3)+3        f(-2)=12(-2)+3          f(0)=12(0)+3        f(1)=12(1)+3    f(2)=12(2)+3

f(-3)= -36+3          f(-2)= -24+3              f(0)= 0+3             f(1)=12+3       f(2)=24+3

f(-3)= -33                f(-2)= -21                  f(0)=3                 f(1)=15           f(2)= 27

Don't know if you wanted all the work. But I just did it for you so you can see.

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