$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$

7 0

3 years ago

Read 2 more answers

7.) Nate has $267 in bills. None of the bills is greater than $10. He has eleven $10 bills. He has seven fewer $5 bills than $1

slavikrds [6]

Just set up 2 equations.

267 = 10(11) + 5(x) + 1(y)
x = y - 7

you can plug the second into the first and get

267 = 110 + 5(y - 7) + y
157 = 5y - 35 + y
6y = 192
y = 32
x = 32 - 7 = 25

thus, 32 $1's and 25 $5's

3 0

3 years ago

Whoever answers the question first and right will get brainly

guapka [62]

Heyyyyyyydbdndnhbdbebe

4 0

2 years ago

What is the sum of 2/3 and 4/5

Ivanshal [37]

Answer:

1 7/15 or 22/15

Step-by-step explanation:

2/3 = 10/15

4/5 = 12/15

3 0

3 years ago