A previous analysis of paper boxes showed that the the standard deviation of their lengths is 9 millimeters. a packer wishes to
find the 98% confidence interval for the average length of a box. how many boxes does he need to measure to be accurate within 3 millimeters?
1 answer:
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Answer:
Make the 8 worth 10 times as much.
Step-by-step explanation:
Step-by-step explanation: Hope this help :D
−4m−2 1/4−6 1/4
Answer: =−4m−8 1/2 (Decimal: -4m+\,{-17}/{2}\,)
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Answer:
3^7
Step-by-step explanation:
Use exponent rules
a^b * a^c = a^(b+c)
3^5 * 3^2 = 3^(5+2)
Answer:
i/=-d:./k/-= sorry
Step-by-step explanation:
