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statuscvo [17]
3 years ago
14

-31+(-42)= 38+(-43)=

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

-31+(-42)= -31-42 = -73

38+(-43)= 38-43 = -5

(-) - (-) = +

(-)+(-) = +

(-)+(+) = -

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For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
3 years ago
I'm completely lost?
aliya0001 [1]
13000-5600=7400...that's about it, just multiply then subtract
4 0
3 years ago
Read 2 more answers
8 + 3 (16 - 12). Help thanks
PSYCHO15rus [73]

Answer:

20

Step-by-step explanation:

you've got to do the inside parenthesis first then multiple with 3 and finally add 8

8 0
3 years ago
Read 2 more answers
1.6x=1.28<br> help me solve this
bogdanovich [222]

Answer:

Step-by-step explanation:

Sure! So, we need to divide by 1.6 on each side to isolate the x.

1.6x / 1.6 is just x. We need to divide by the same on the other side too!

1.28 / 1.6 is 0.8.

So x = 0.8

7 0
3 years ago
Find the midpoint of points A(-2,-8) and B(7,-4) graphically.
k0ka [10]

Answer:

The midpoint is (2.5,-6) or written as a fraction (\frac{5}{2}, -6)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2} ) \\MP= (\frac{-2+7}{2}),(\frac{-8+-4}{2} ) \\MP= (\frac{5}{2}),(\frac{-12}{2} ) \\MP= (2.5,-6 )

7 0
3 years ago
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