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The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
90 degrees means 90 degrees counterclockwise. So from the fourth quadrant we'll end up in the first quadrant. X and Y get swapped and one negated, it must be the -2 becoming 2, so our image is
(2,5)
Answer: A
Answer:
Step-by-step explanation:
I think the answer C x=42 y=30, correct me if i'm wrong
Answer:
40.8
Step-by-step explanation:
