Determine the relation of the following lines: y = -2x + 4 and y = -2x + 1.
1 answer:
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Answer:
a) P(0, <u>2</u>), Q(<u>4</u>, 0)
b) Please find attached the plot of the points P and Q on a chart made with MS Excel
c) Please find the graph of the line that represent the function 4·x + 2·y = 8 for values of x from -2 to 3 made with the Insert Chart feature on MS Excel
Step-by-step explanation:
The given equation for the line is 4·x + 2·y = 8
a) The coordinates of P = P(0, _)
Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)
When y = 0 from the given equation, we get;
4·x + 2·y = 8
At the point y = 0;
4·x + 2 × 0 = 8
x = 8/4 = 2
x = 2
∴ The coordinates of P = P(0, _) = P(0, <u>2</u>)
Similarly, when x = 0, we get;
4·x + 2·y = 8
At the point x = 0;
4 × 0 + 2·y = 8
y = 8/2 = 4
y = 4
∴ The coordinates of Q = Q(_, 0) = Q(<u>4</u>, 0)
b) Rewriting the given equation in terms of 'y' gives;
y = (8 - 4·x)/2 = 4 - 2·x
y = 4 - 2·x
With the help of MS Excel, the points P and Q are plotted in the attached graph
c) The line of the graph of the function 4·x + 2·y = 8 for values of x from -2 to 3 can be added by Changing the Chart Type to 'Scatter with Smooth Lines and Markers' within MS Excel as presented in the included graph of the line.
Take the cross product, then normalize the result.
This has norm
and so a unit vector orthogonal to both given vectors is
An equally correct answer would be the negative of this vector, since
.
This has norm
and so a unit vector orthogonal to both given vectors is
An equally correct answer would be the negative of this vector, since