Simplify the expression.6*6^t-2*6^t

You flip a coin that is not fair, the prbability of heads on each flip is 0.7. if the coin shows heads, you draw a marble from u

Shkiper50 [21]

Solution :

P(H) = 0.7 ; P(T) = 0.3

If heads, then Urn H, 1 blue and 4 red marbles.

If tails, then Urn T , 3 blue and 1 red marbles.

a).

P ( choosing a Red marble )

= P (H) x P( Red from Urn H) + P (T) x P( Red from Urn T)

$=0.7 \times \frac{4}{5} + 0.3 \times \frac{1}{4}$

= 0.56 + 0.075

= 0.635

b). If P (B, if coin showed heads)

If heads, then marble is picked from Urn H.

Therefore,

P (Blue) $=\frac{1}{5}$

= 0.2

c). P (Tails, if marble was red)

$=P (T/R) = \frac{P(R/T)}{P(R)} \ P(T)$

Where P (R/T) = P ( red, if coin showed tails)

$=\frac{1}{4}$

= 0.25 (As Urn T is chosen)

P (R) = P (Red) = 0.635 (from part (a) )

P (T) = P (Tails) = 0.3

∴ $P(T/R) = \frac{0.25 \times 0.3}{0.635}$

= 0.118

8 0

3 years ago

I need help ASAP!!!! Please help. I will give brainliest!!!

Sidana [21]

HELLO the answer is 33!!!

7 0

3 years ago

Can anyone help me with these questions there is a photo of them the question of the triangle is find the value of a

Olin [163]

13. a^2+7^2=15^2

a^2+49=225

-49=-49

a^2=176

a=13.266

14. 4 more girls chose soccer over softball.

15. I think it's a negative correlation or you have to find dots that can make a line

16. 3

4 0

4 years ago

Use a number line to approximate the value of root 33

dsp73

Let's think about the square root of 33 here for a second.

What two perfect squares surround 33?

The answer is 25 and 36.

Then, let's take the square root of both 25 and 36, which are 5 and 6. Therefore, since the square root of 25 and 36 are both nearest to the square root of 33, then the square root of 3 must be between 5 and 6.

The correct answer is A (or option 1): 5 < root 33 < 6

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(

Strike441 [17]

Answer:

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Step-by-step explanation:

The average rate of change formula is:

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}}$

a.

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0 so

$x_{1} = -3$

$y_{1} = 0$

At x = -2 it looks like y = 2

$x_{2} = -2$

$y_{2} = 2$

Now we can just plug everything in to the rate of change formula.

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{2- 0}{-3-(-2)} = \frac{2- 0}{-3+2} = \frac{2}{-1}$ = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

$x_{1} =$ -2

$y_{1} =$ 2

$x_{2} =$ 1

$y_{2} =$ - 4

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{-4- 2}{1-(-2)} = \frac{-4-2}{1+2} = \frac{-6}{3}$ = -2

c.

$x_{1} =$ 0

$y_{1} =$ -3

$x_{2} =$ 1

$y_{2} =$ - 4

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{-4-(-3)}{1-0} = \frac{-4 + 3}{1-0} = \frac{-1}{1}$ = -1

d.

$x_{1} =$ 1

$y_{1} =$ -4

$x_{2} =$ 2

$y_{2} =$ 0

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{0 - (-4)}{2-1} = \frac{0 + 4}{2-1} = \frac{4}{1}$ = 4

e.

$x_{1} =$ -1

$y_{1} =$ 0

$x_{2} =$ 0

$y_{2} =$ -3

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{-3- 0}{0-(-1)} = \frac{-3- 0}{0+1} = \frac{-3}{1}$ = -3

f.

$x_{1} =$ -1

$y_{1} =$ 0

$x_{2} =$ 2

$y_{2} =$ 0

$\frac{y_{2}- y_{1}}{x_{2}-x_{1}} = \frac{0- 0}{2-(-1)} = \frac{0- 0}{2+1} = \frac{0}{3}$ = 0

4 0

3 years ago