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Pavel [41]
3 years ago
7

Find the range of the relation {(–1, 4), (2, 5), (3, 5)}. Then determine whether the relation is a function.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0
The range is the y values of the function. So it would be (4,5). In order for the relation to be a function, it has to pass the vertical line test. That means that one singular x value cannot equal two different y values. It makes no sense if you really think about it. You can’t plug two different x values into the same function and get the same y value. There’s no repeat in x values, so the relation is a function
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horsena [70]

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3 0
3 years ago
Expand and simplify (x+5)(x+2)
Savatey [412]
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F:First
O:Outer
I:Inner
L:Last

So, given the expression (x+5)(x+2), lets multiply the first two terms.

x*x=x²

now the outer two terms

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now the inner terms

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and the last terms...

5*2=10

When we combine these expressions we get:

x²+7x+10

I think this is what you meant to be answered in your question, if I have been mistaken, just comment and I'll edit my answer....

5 0
3 years ago
Solve 9/10=z/8 . Round to the nearest tenth.
kompoz [17]
\boxed {Question}
\frac{9}{10} =  \frac{z}{8}

\boxed {Cross \  multiply}
10z = 8 \times 9

\boxed {Evaluate}
10z = 72
z = 72 \div 10
z = 7.2

\Longrightarrow \bf \ Answer \ : \ z = 7.2

4 0
3 years ago
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