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Morgarella [4.7K]
3 years ago
15

An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o

f the average total weight of 185 pounds (passenger weight including shoes, clothes, and carry-on). Suppose that a random sample of 51 passengers showed an average total weight of 200 pounds with a sample standard deviation of 59.5 pounds. Assume that passenger total weights are normally distributed. What are the appropriate null and alternative hypotheses?
Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

H_{0}: \mu= 185 and H_{a}: \mu > 185

Step-by-step explanation:

The null hypothesis H_{0} states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form H_{0}: parameter = value

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form H_{0}: \mu= 185.

The alternative hypothesis H_{a} states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use H_{a}: \mu > 185 as his alternative hypothesis.

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Answer:

40

Step-by-step explanation:

Use the Outside Angles Theorem,

\frac{110 - 30}{2}  = 40

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3 years ago
Nina can ride her bike 63,360 feet in 3,400 seconds, and Sophia can ride her bike 10 miles in 1 hour. What is Nina's rate in mil
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4 years ago
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How many commuters must be randomly selected to estimate the mean driving time of Chicago commuters? We want 95% confidence that
zimovet [89]

Answer:

61 commuters must be randomly selected to estimate the mean driving time of Chicago commuters.                

Step-by-step explanation:

Given : We want 95% confidence that the sample mean is within 3 minutes of the population mean, and the population standard deviation is known to be 12 minutes.

To find : How many commuters must be randomly selected to estimate the mean driving time of Chicago commuters?

Solution :

At 95% confidence the z-value is z=1.96

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n is the number of sample

The formula of margin of error is given by,

E=\frac{s\times z}{\sqrt{n}}

Substitute the value in the formula,

3=\frac{12\times 1.96}{\sqrt{n}}

3=\frac{23.52}{\sqrt{n}}

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Squaring both side,

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Therefore, 61 commuters must be randomly selected to estimate the mean driving time of Chicago commuters.

6 0
3 years ago
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Answer:

\sqrt{106}

Step-by-step explanation:

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4 0
4 years ago
X - y = 3<br> x + 3y = 9
Ugo [173]
Solve for one of the variables in the first equation (in this case, I will solve for X):
X = Y + 3

Then use that value of X in the second equation to solve for Y:
X + 3Y = 9
(Y + 3) + 3Y = 9
4Y + 3 = 9
4Y = 6
Y = 1.5

Use the value of Y we just found in the X equation we created:
X = Y + 3
X = 1.5 + 3
X = 4.5

Therefore X = 4.5 or 9/2 and Y = 1.5 or 3/2.
7 0
3 years ago
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