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Morgarella [4.7K]
3 years ago
15

An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o

f the average total weight of 185 pounds (passenger weight including shoes, clothes, and carry-on). Suppose that a random sample of 51 passengers showed an average total weight of 200 pounds with a sample standard deviation of 59.5 pounds. Assume that passenger total weights are normally distributed. What are the appropriate null and alternative hypotheses?
Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

H_{0}: \mu= 185 and H_{a}: \mu > 185

Step-by-step explanation:

The null hypothesis H_{0} states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form H_{0}: parameter = value

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form H_{0}: \mu= 185.

The alternative hypothesis H_{a} states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use H_{a}: \mu > 185 as his alternative hypothesis.

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Solve by taking the square too of both sides.<br> 3(c+3)^2-81=0
Norma-Jean [14]

Answer:

x = -3 ±3sqrt(3)

Step-by-step explanation:

3(x+3)^2-81=0

Add 81 to each side

3(x+3)^2=81

Divide each side by 3

3/3(x+3)^2=81/3

(x+3)^2=27

Take the square root of each side

sqrt ((x+3)^2)=±sqrt(27)

x+3 =±sqrt(9*3)

x+3 =±sqrt(9)*sqrt(3)

x+3 =±3sqrt(3)

Subtract 3 from each side

x = -3 ±3sqrt(3)

7 0
3 years ago
Simon Whitfield Victoria, British Columbia, won the men's triathlon at the Sydney Olympics. The race consisted of 1.5 km swim in
Over [174]

Total triathlon distance →1.5 km + 40km  + 10 km = 51.5 km

So 51.5 km represents 100% of distance covered.

The % of each component = (distance of component/Total distance) multiplied by 100% so :

% of swim → (1.5 / 51.5) × 100 → 0.029 × 100 = 2.9%

% of bike ride → (40 / 51.5) × 100 →0.776 × 100 = 77.6%

% of  run → (10 / 51.5) × 100 → 0.194 × 100 = 19.4%

Percentage spent on land  will be

(40 km bike ride + 10 km run / Total triathlon distance) multiplied by 100%

(50 / 51.5) × 100 → 0.970 ×100 = 97%


5 0
4 years ago
The rocket that will return the rock and soil samples to Earth cannot lift off if the total weight of the samples from the rover
yuradex [85]

Binomial distribution will be used to know the probability that the total weight of the samples will exceed 530 pounds.

It is given that the rocket that will return the rock and soil samples to Earth cannot lift off if the total weight of the samples from the rovers exceeds 530 pounds.

In probability theory and statistics, the binomial distribution with parameters n and p is the discrete probability distribution of the number of successes in a sequence of n independent experiments, each asking a yes–no question, and each with its own Boolean-valued outcome: success (with probability p) or failure (with probability q = 1 − p). A single success/failure experiment is also called a Bernoulli trial or Bernoulli experiment, and a sequence of outcomes is called a Bernoulli process; for a single trial, i.e., n = 1, the binomial distribution is a Bernoulli distribution. The binomial distribution is the basis for the popular binomial test of statistical significance.

To know more about binomial distribution visit: brainly.com/question/14565246

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3 0
2 years ago
Please assist me with this problem
Anna11 [10]

Answer:

Option B is not a justification

Step-by-step explanation:

Option A is a justification (to get two pair of similar triangles (ABC-ACD) and (ABC-BCD))

Option C is a justification (a^2 = cy, b^2 = cx, a^2 + b^2 = cy + cx)

Option D is a justification (a^2 + b^2 = cy + cx = c(y + x) = c^2)

=> Option B is not a justification

8 0
3 years ago
a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.
Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
  • Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

To find the second term a_{2}, use the recursive rule a_{n} = a^{n-1} \times r

⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

3 0
4 years ago
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