Answer:
D. 
Step-by-step explanation:
Area of rectangle = 
Length of rectangle = (x - 8)
Width = (x + 11)
Area of rectangle = 
Expand the expression
(distributive property of multiplication)
Combine like terms
Expression for the area of the rectangle =
Answer:
3 toppings
Step-by-step explanation:
14.75(total)-9.50(pizza)
=5.25 / 1.75(each topping)
3 toppings
Answer:
i) 
\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii)
4^{3} + 8^{2} + \sqrt{9}
iii) ![(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B5%7D%29%5E%7B2%7D.%20%5Csqrt%5B3%5D%7B8%7D%20%5Cleqx%5E%7B3%7D%20-%203x%20%2B%206%20%5Cleq%20%5Csqrt%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5CRightarrow%20%5Chspace%7B0.2cm%7D)
(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
Step-by-step explanation:
i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii) 4^{3} + 8^{2} + \sqrt{9}
iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
Answer:
Step-by-step explanation:
The domain is given in the set-builder form and it is the set of all real numbers greater than 8.
i.e., the domain is (8, ∞).
Now, consider the function f(x) = . This function accepts all real numbers greater than 8 as input.
But, for values less than 8, the output is not real.
Hence, is the required function.
