Answer:
6. E
7. D
8. 5,-8,34
Step-by-step explanation:
A. Parallel to the y-axis and passes through the point (3,5)
For it to be parallel to the y-axis, what this means is that it has an x-intercept and no y intercept.
So what this means is that x = 3 is our line so E is correct
B. Perpendicular to the y-axis means it is parallel to the x-axis
It means is has no x intercept and thus its x value at any point in time is zero
So the equation is y = -5
or simply y + 5 = 0 which means D is correct
C. It is parallel to the line 5x -8y + 12 = 0
Thus: 8y = 5x + 12
dividing both sides by 8
y = 5x/8 + 12/8
y = 5x/8 + 3/2
y = 5x/8 + 1.5
Comparing this with the general equation of a straight line ;
y = mx + c
where m is that slope, this means that 5/8 is the slope of the line
Mathematically if two lines are parallel, they have equal slopes.
So we can say the slope of the other line too is 5/8
Now to find the equation of the other line, we can use the point-slope method
y-y1 = m(x-x1)
where (x1,y1) in this case is (-2,3)
So we have;
y-3 = m(x-(-2))
y-3 = 5/8 (x + 2)
8(y-3) = 5(x + 2)
8y -24 = 5x + 10
5x + 10 + 24 -8y = 0
5x -8y + 34 = 0
So A, B, C = 5, -8, 34
Find the absolute value vertex. In this case, the vertex for y=|x−5|y=|x-5| is (5,0)(5,0).
(5,0)(5,0)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
(−∞,∞)(-∞,∞)
{x|x∈R}{x|x∈ℝ}
For each xx value, there is one yy value. Select few xx values from the domain. It would be more useful to select the values so that they are around the xx value of the absolute valuevertex.
xy3241506172
Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Answer:
what is your questions mate I mm didn't understand ¯\_(ツ)_/¯
Step-by-step explanation:
,When a percent amount is multiplied to another number, the operation produces a value that equals the given percent of the original number. ... Multiplying a number by 100 percent is a just variation of the multiplicative identity and will result in the value being unchanged.
