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Cloud [144]
3 years ago
9

Evaluate -2x 2 y, if x = -3 and y = -1. -12 -18 18 12

Mathematics
2 answers:
Andru [333]3 years ago
8 0

Answer:

18

Step-by-step explanation:

xeze [42]3 years ago
5 0

Answer:

18

Step-by-step explanation:

-2 x^2y

Let x=-3 and y = -1

-2 (-3)^2 (-1)

-2 (9) (-1)

18

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In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5
Nat2105 [25]

Answer:

0.79, - 2.12

Step-by-step explanation:

7 0
3 years ago
3+p/2=6 How do I solve this?
Diano4ka-milaya [45]

\boxed{\underline{\bf \: ANSWER}}

\sf\frac { 3 + p } { 2 } = 6 \\

Multiply both sides by 2.

\sf \: 3+p=6\times 2

Multiply 6 and 2 to get 12.

\sf \: 3+p=12

Subtract 3 from both sides.

\sf \: p=12-3

Subtract 3 from 12 to get 9.

\boxed{\bf \: p=9}

____

Hope it helps.

RainbowSalt2222

5 0
3 years ago
Write a system of two linear equations showing the distance each animal can
pantera1 [17]

Answer:

X

Step-by-step explanation:

X=input(time) 6 minutes both

3 0
3 years ago
Question 3.<br> How do you write 4% as a decimal?<br> A) 0.4<br> B) 0.40<br> C) 0.04
AnnyKZ [126]
C. 0.04 would be the correct answer.
5 0
3 years ago
Read 2 more answers
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
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