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Luden [163]
3 years ago
14

The table below shows the ages of employees over 50 at a company and the amount of money they have in their retirement accounts.

Describe the relationship between the two sets of data and what it means in the problem situation. A. Strong positive B.Strong negative C.No association

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

c

Step-by-step explanation:

plot your graph and then you will see there is no line which shows there is a correlation. they're too scattered

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Are the following lines parallel perpendicular or neither y=-5/3x - 5 and y=4/3x - 5​
katrin [286]

Answer:

neither

Step-by-step explanation:

For lines to be parallels the slopes must be equal, for the lines to be perpendicular the lines have to be inverse reciprocals  meaning if you have a slope of 1/2X then the perpendicular line must be -2X

3 0
2 years ago
The time to complete a standardized exam is approximately normal with a mean of 70 minutes & a standard deviation of 10 minu
Gennadij [26K]

if the mean is 70 minutes, then 90 minutes is 2 standard deviations above 70. if you look at the bell curve i drew, the percent of exams that took over 90 minutes is 2.5% <span>
</span>
7 0
3 years ago
Read 2 more answers
Right now, Simran's father is three times as old as Simran. Five years ago, he was four times as
Illusion [34]
Hello,

Let's f the age of the father
s the age of Simran

f=3*s
f-5=4*(s-5)
==>3s-5=4s-20
==>s=15
f=3*15=45


3 0
3 years ago
Read 2 more answers
An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand
stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis H_{0} =µ  =800

alternative hypothesis  H_{1} = µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

                             t = \frac{788-800}{\frac{45}{\sqrt{30} } }

                       t = \frac{12}{8.215} = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

7 0
3 years ago
Select all of the following expressions that are equivalent to 16a+40 .
lina2011 [118]
The first one is true
<span>4(4a+10)  is 
</span>16 a + 40 after distribution

The second one is also true
<span>2(8a+20) 
16a + 40 after distribution

Third is not true
</span><span>4a(4+10a) 
</span><span>16a + 40a^2 after distribution

Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution

Hope this helps :)</span>
5 0
3 years ago
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