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Amiraneli [1.4K]
3 years ago
5

Can you please solve a it is so important

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0
F(x)=-x2+5n
g(x)=-2n+15
A(x)=|g(x)-f(x)|=|x2-7n+15|
x2-7n+15>0 for every x (1)
A(x)=x2-7n+15

(1):
x2-7n+15=(x-3.5)^2-12.25+15=(x-3.5)^2+2.75 > 0
because for every x: (x-3.5)^2>=0

answer: A(x)=x2-7n+15

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Help please, will mark brainliest ​
mario62 [17]

Answer:

Step-by-step explanation:

LET ORANGES=X

PEARS ARE 3 TIMES =3X

LET CHILDREN=Y

IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X

X=5Y........................I

IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS

8Y+21=3X....................II

SUBSTITUTING FOR X FROM EQN.I..

8Y+21=3*5Y

15Y-8Y=21

7Y=21

Y=3

X==5Y=5*3=15..

SO CHILDREN =3

ORANGES=15

PEARS=3*15=45

THANKYOU AND PLEASE AMRK IT BRAINLIEST

8 0
3 years ago
Find the real solutions of the equation by graphing
Vlada [557]

Answer:

C. 0, 1.29, -0.65

Step-by-step explanation:

The real solutions of the equation 19x^3-12x^2-16x=0  is where the graph of y=19x^3-12x^2-16x intersects the x-axis.

This means that we need to graph y=19x^3-12x^2-16x using a graphing software.

From the graph shown in the attachment x=0, x=1.29, and x=-0.65  are the  real solutions.

The correct choice is C

8 0
3 years ago
Mhm help please! quarantine got me
Karolina [17]
The answer would be 9.4
3 0
3 years ago
Read 2 more answers
Question in the picture below
tekilochka [14]
The answer is C . cube 2
Explanation:
Using PEMDAS its Parentheses, exponents ,multiple then divide and add , subtract
8 0
2 years ago
Read 2 more answers
Solve the equation using the quadratic formula : x^2-10x+25=18
Sever21 [200]
x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}

x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}


8 0
3 years ago
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