All categories

3 years ago

Use the quadratic formula to determine the exact solutions to the equation. 2x^2−5x+1=0

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

5±√17

Step-by-step explanation:

2x^2−5x+1=0

5 ±√25 - 4 (2)(1) = 5±√17

2 ( 2) 4

You might be interested in

Suppose payments were made at the end of each month into an ordinary annuity earning interest at the rate of 4.5%/year compounde

valentina_108 [34]

Answer:

each payment = $214.20

Step-by-step explanation:

For ordinary annuity,

FVOA = PMT x [{(1+r/m)^(n*m)} - 1/(r/m)]

Here, FVOA = $50,000

year, n = 14

Since the interest will be paid monthly, m = 12

interest rate, r = 4.5% = 0.045

PMT = ?

Putting all the values into the ordinary annuity formula,

FVOA = PMT x [{(1+r/m)^(n*m)} - 1/(r/m)]

$50,000 = PMT x [{(1+0.045/12) ^ (14*12)} - 1/(0.045/12)]

or, $50,000 = PMT x [{(1+0.045/12) ^ (14*12)} - 1/(0.045/12)]

or, $50,000 = PMT x [(1.8754 - 1)/0.00375]

or, $50,000 = PMT x 233.4399

or, PMT = $50,000/233.4399

PMT = $214.19

or, monthly payment will be $214.20 (Nearest cent)

7 0

3 years ago

Which of the following is a polynomial with roots 5, 7, and −8?

Cloud [144]

X^3-4x^-61x+280 factors are x-5 x-7 x+8
plz rate brainliest

4 0

4 years ago

Read 2 more answers

What happens to a figure that is dilated by a factor of 13

USPshnik [31]

Answer: it gets smaller, 13 times smaller

Step-by-step explanation:

Size of the figure/13

7 0

3 years ago

a population has a mean of 25 median of 24 and mode of 26 the standard deviation is 5 the value for the

Arada [10]

Complete Question

A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.

Answer:

The value of the 16th percentile is $x = 20$

The range for the middle 3 standard deviation is $10 \to 40$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 25$

The median is $m = 24$

The mode is $n = 26$

The standard deviation is $\sigma = 5$

Generally the 16th percentile is mathematically represented as

$P(x)= P(\frac{X - \mu }{ \sigma } \le \frac{x- 25 }{5} ) = 0.16[/teGenerally [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )$

$P(x) = P(Z \le \frac{ x - 25}{5} ) = 0.16$

Now from the normal distribution table the z-score of 0.16 is

z = -1

$P(x) = P(Z \le \frac{ x - 25}{5} ) = P(Z \le -1 )$

=> $\frac{x- 25}{5} = -1$

=> $x- 25 = -5$

=> $x = 25-5$

=> $x = 20$

The range for the middle 3 standard deviation is mathematically represented

$\mu - 3\sigma \to \mu + 3\sigma$

$25 - 3(5 ) \to 25 + 3(5 )$

$10 \to 40$

3 0

3 years ago

Which critical value is appropriate for a 99% confidence level where nequals17, sigma is unknown, and the population appears

My name is Ann [436]

Answer:

t Subscript alpha divided by 2 = 2.921

Step-by-step explanation:

With sample sizes lower than 30, we use the t-test.

Otherwise, we use the z-test.

Here, n = 17

So we use the t-test.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 17 - 1 = 16

Now, we have to find a value of T, which is found looking at the t table, with 16 degrees of freedom(y-axis) and a confidence level of 0.99( $t_{1 - (\frac{1-0.99}{2}}) = 0.995$ ). So we have T = 2.921

So the correct answer is:

t Subscript alpha divided by 2 = 2.921

6 0

4 years ago

Read 2 more answers