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timurjin [86]
3 years ago
9

Larry has a clay brick that is 7 inches long, 5.5 inches wide, and 2.75 inches thick, the same size as the gold stored in a vaul

t in the form of gold bars. Find the volume of this brick. If the weight of the clay in the brick is 0.1 pound per cubic inch and the weight of the gold is 0.7 pound per cubic inch, find the weight of the brick and the gold bar. Round all answers to the nearest tenth.
Mathematics
2 answers:
Sati [7]3 years ago
6 0
The volume of the brick is 105.9 cubic inches and the weight of the brick is 10.6 pounds and the weight of the gold brick is 74.1 pounds
lana [24]3 years ago
5 0
Add the subtract then u will get ur answer
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Find the value of x.
Firdavs [7]

Step-by-step explanation:

DC is equal to 180°, so subtract 105 from 180.

180-105=75

180 is the total of the the angles when added together.

67°+75°=142

180-142=38

x=38

8 0
4 years ago
I’m so confused need help of the height Or the light house
Alina [70]
Use a proportion.

2.2/5.5 = 48/x

2.2x = 5.5 * 48

2.2x = 264

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4 0
3 years ago
Simplify the following expression.<br> 3(x + 2) - 5x
tankabanditka [31]

Answer:

It should be -2x +6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of X! Please help!
nydimaria [60]
ANSWER

x = 8 \sqrt{3}

EXPLANATION

{h}^{2} = {y}^{2} + {4}^{2}
This implies that,

{h}^{2} = {y}^{2} + 16...eqn1

Also,

{h}^{2} + {x}^{2} = {16}^{2} ...eqn2

And

{y}^{2} + {12}^{2} = {x}^{2}

{y}^{2}={x}^{2} - 144 ...eqn3

Put equation 1 into equation 2.

This will give us,

{y}^{2} + 16 + {x}^{2} = {16}^{2}

{y}^{2} +{x}^{2} = {16}^{2} - 16

{y}^{2} +{x}^{2} =16 ( 16 - 1)

{y}^{2} +{x}^{2} =240...eqn4

We put equation 3 into equation 4,

{x}^{2} - 144+{x}^{2} =240

We simplify to get,

2 {x}^{2} = 384

{x}^{2} = 192

x = \sqrt{192}

x = 8 \sqrt{3}
4 0
3 years ago
Patrick owns an apartment building. He knows that the money he earns in a month depends on the rent he charges. The relationship
belka [17]

E=13,000 and<span>E=1/50R(1650-R)</span>

<span>
</span>

<span />0.02R(1650-R)=13000

<span>(0.02R)(1650)-0.02R²=13000</span>

<span /><span>0.02R²-33R+13000=0</span>

<span>R2-1650R+650000=0</span>

<span>SOLVE W QUAD FORMULA
</span>

7 0
3 years ago
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