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pantera1 [17]
2 years ago
5

With a short time remaining in the day, a delivery driver has time to make deliveries at 5 locations among the 9 locations remai

ning. How many different routes are possible?
There are possible different routes.
Mathematics
1 answer:
Delvig [45]2 years ago
5 0

Answer:

15,120

Step-by-step explanation:

The computation of the number of different routes are possible is shown below:

Since there are 5 locations for deliveries among the 9 locations that left

So, the number of routes that could be possible is

= ^9P_5\\\\= \frac{9!}{9-5!} \\\\= \frac{9!}{4!} \\\\=  \frac{9\times 8\times 7\times 6\times 5\times 4!}{4!}\\\\= 15,120

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<span>What is the sum of all the interior, exterior, and central angles in a convex hexagon?
INTERIOR=180
EXTERIOR=360
CENTRAL=360</span>
5 0
2 years ago
What is the distance between the points (4,5) and (10,13) on a coordinate plane?
Readme [11.4K]
The distacne between the points (x1,y1) and (x2,y2) is
D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so

D=\sqrt{(10-4)^2+(13-5)^2}
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7 0
2 years ago
HELP ASAP
zavuch27 [327]
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6 0
2 years ago
Read 2 more answers
2x^2+16x+42=0 what is the answer?
Debora [2.8K]

Answer:

no solution

Step-by-step explanation:

With some linear expressions, like this one, that has an answer of 0 has no solution

3 0
3 years ago
The number of acres a farmer uses for planting pumpkins will be at least 2 times the number of acres for planting corn. The diff
jeka94

Answer:

Step-by-step explanation:

A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:

  x ≥ 2y . . . . . pumpkin acres are at least twice corn acres

  x - y ≤ 10 . . . . the difference in acreage will not exceed 10

  12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18

  0 ≤ y . . . . . the number of corn acres is non-negative

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B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...

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__

C) see below for a graph

__

D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.

So profit is maximized for 18 acres of pumpkins and 9 acres of corn.

Maximum profit is $360·18 +$225·9 = $8505.

7 0
3 years ago
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