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Oliga [24]
3 years ago
9

What is the range of the graph (5,3) (2,5) A) 3 < y < 5 B) 3 ≤ y ≤ 5 C) 2 < x < 5 D) 2 ≤ x ≤ 5

Mathematics
1 answer:
Tresset [83]3 years ago
7 0

Answer:

B

Step-by-step explanation:

domain is the set of x-values

range is the set of y-values (corresponding to the x-values)

Now, since we want the range, we can immediately eliminate Choices C  &  D because they dealing with the DOMAIN ONLY (since x values).

Now, we have to choose from option A or option B.

The only difference is the greater than or less than sign with "equal to" signs as well. Whenever we are given 2 coordinate points, we can say that ALWAYS, we can graph a line segment using these 2 points. And line segments are all SOLID {meaning that the endpoints are INCLUDED).

What we mean by included is that the inequality sign should have "equal to" with it. Also, the two values of y-values are 3 and 5, thus range would be between 3 and 5 (inclusive). We can write:

Range = 3 ≤ y ≤ 5

Correct choice is B

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The correct option is

The origin is included in the shaded region and the shaded area is below the line.

Step-by-step explanation:

Y>3/2x + 2

Put x=0

Y= 2

(0,2)

Put y=0

X= -4/3

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See attached picture for the sketch

3 0
3 years ago
An office needs 300 envelopes. If there are 30 envelopes in each box, how many boxes should the office buy?
Mila [183]

Answer:

they should buy 10 boxes

Step-by-step explanation:

300/30 = 10

7 0
2 years ago
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For graph f what is f(0)?
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Answer:

2

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3 0
2 years ago
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

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2 years ago
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How can i find the area of this triangle?
Ivanshal [37]
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