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algol [13]
3 years ago
11

Simplify. this please​

Mathematics
2 answers:
frez [133]3 years ago
4 0

Answer: -125p12z18u3

Reason:

Square negative five twice, so: -5 x -5 x -5 = -125

The first squaring is -5 x -5, which is 25. The second squaring is 25 x (-5), which is - 125.

When it comes to the letters, they act like they are being multiplied.

(p4)3 = p12

(z6)3 = z18

(u)3 = u3

So the answer is -125p12z18u3.

Hope this helps! :)

katen-ka-za [31]3 years ago
3 0

First you have to know the "power rule." This is when there is an exponent outside the parentheses and some/all of the variables/numbers in the parentheses have exponents as well. What you do is multiply the outer exponent with each of the exponents inside the parentheses.

((-5)^{1*3} p^{4*3} z^{6*3} u^{1*3} )

(-5)^{3}p^{12}z^{18}u^{3}

-125p^{12}z^{18}u^{3}

Hope this helped!

~Just a girl in love with Shawn Mendes

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Alja [10]

0.05 = 5% = 5/100

Simplify 5/100 and you get 1/20.


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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

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We simply applied the above formulas so that the each part could come

8 0
3 years ago
Is 1/4 of 8 equal to 2
Svet_ta [14]
Yes, 1/4 of 8 is equal to two.
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A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet
Natali5045456 [20]

Complete Question

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet from the ground and he catches it when it is four feet from the ground,How long is the ball in the air?

Answer:

t\approx 0.1s

Step-by-step explanation:

From the question we are told that

Initial velocity  V_0= 18 ft/s

Initial Height    h_1=5feet

Final Height     h_2=4feet

Generally the Newtons equation for motion is mathematically given by

   V^2 = U^2 + 2as

Where

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And

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Therefore

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   V^2 = 388.4

   V =19.70786645\\V=19.71ft/s

Generally the equation for Time is mathematically Given as

   t=\frac{V-U}{a}

   t=\frac{19.71-18}{32.2}

   t=0.05310559006

   t\approx 0.1s

Therefore the time spent on air by the ball is

    t=0.05310559006s

4 0
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