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2 years ago

The concentration of Salt Satulom is teams

Mathematics

1 answer:

Inessa [10]2 years ago

8 0

Answer:

110

Step-by-step explanation:

20/100×550=110

so that how to solve it

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The cup, on the 9th hole of a golf course, is located, dead center, in the middle of a circular green, which is 35 feet in radiu

ale4655 [162]

Answer:

± 27.33 ft

Step-by-step explanation:

For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:

(-50-0)/(-40-0) = 50/40 = 1.25

Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.

Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);

-0.8 = y/x

y = -0.8x

Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:

35^2 = x^2 + y^2

y = -0.8x

35^2 = x^2 + (-0.8x)^2

1225 = (x^2 + 0.64x^2)

1225 = 1.64x^2

x^2 = 1225/1.64 = 746.95

x = sqrt(746.95) = ± 27.33 ft

5 0

3 years ago

Q10 A student wants to raise £100 for charity.

ElenaW [278]

Answer:

He must charge minimum £0.84 for one hot dog.

Step-by-step explanation:

Ingredients cost for hot dogs at the supermarket,

Price of dog sausages tin of 8 = 50p ≈ £0.5

Price of dog bun packs of 6 = 90p ≈ £0.90

Number of tins required for 150 hot dogs = $\frac{150}{8}$ = 6.25

So student will purchase 7 tins.

Cost of 7 tins = 7 × 0.5

= £3.5

Number of dog buns packets required = $\frac{150}{6}$ = 25

Cost of 25 packs = 25 × 0.9

= £22.5

Total cost of the material used for 150 buns = 22.5 + 3.5

= £26.0

Let the selling price of each hot dog = £x

Then selling price of 150 hot dogs = £150x

Students wants the profit = £100

So, Selling price - Cost price = profit

150x - 26 = 100

150x = 126

x = $\frac{126}{150}$

x = £0.84

Therefore, he must charge minimum £0.84 for one hot dog.

8 0

3 years ago

Find the inverse of 2∛(x+2)

Artemon [7]

$y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}$

5 0

3 years ago

Please tell me if I'm right or not

Pepsi [2]

It’s actually 25.2% of boys prefer to play inside

8 0

3 years ago

Is this right. Please help me

My name is Ann [436]

Answer:

ye that is the correct answer

3 0

3 years ago