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3 years ago

You roll a standard number cube. Find P (number less than 4).

1 answer:

5 0

A standard number cube has 6 sides.

P is any number less than 4 (or 3,2, and 1).

3, 2, and 1 are 3 numbers

Place the number 3 over the amount of numbers there is.

3/6.

Simplify. Divide 3 from the numerator and denominator.

(3/6)/(3/3) = 1/2

1/2, or (B) is your answer

hope this helps!

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PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B%20x%20%2B%202%7D%20%20%3D%2012" id="TexFormula1" title="3 \sqrt[3]{ x +

joja [24]

Answer:dont know

Step-by-step explanation:

sorry

8 0

2 years ago

Helppp!!! 0_o 70 pnts!!!

kati45 [8]

Answer:

Option A is correct

Step-by-step explanation:

For the box y=mx+c

Hope this helps

8 0

2 years ago

Read 2 more answers

Without calculating, which has a bigger volume. A cube that has a length, width, and height of 18 m. Or a sphere with a radius o

Evgesh-ka [11]

Weird. A period appears above this... huh.

Answer:

[Th]e cube has a greater value.

Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4 $\pi$ r^2 when r = 9? And here's how to solve that.

Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?

A=6(18)^2 Substitute numbers.

A=6(324) Solve ex[p]onents.

A=1944 Mult[i]ply.

So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4 $\pi$ r^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.

A=4(3.14)(9)^2 Subst[i]tute numbers.

A=4(3.14)(81) Solve expone[n]ts.

A=12.56(81) Multip[ly].

A=1017.36 Multiply again[.]

Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.

And PLEASE don't copy this guys. Make your own iteration. Change it up!

3 0

3 years ago

Round 96.466 to the nearest hundredth=

DedPeter [7]

96.47 would be your answer rounded to the nearest hundredth

3 0

3 years ago

Read 2 more answers