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denis23 [38]
3 years ago
5

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0

Answer:

Please see attached image

Step-by-step explanation:

We can work on the products of binomials using distributive property to multiply every term of the first binomial by every term of the second one. Finally combine like terms to get the trinomial that results:

1) (2+a)(2+a)=4+2a+2a+a^2=4+4a+a^2

2) (2a+1)(2a+1)=4a^2+2a+2a+1=4a^2+4a+1

3) (2a-1)(2a-1)=4a^2-2a-2a+1=4a^2-4a+1

4) (2-a)(2-a)=4-2a-2a+a^2=4-4a+a^2

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The mean of this data is: 11

The median of this data is: 11

The mean and median of this data is the same in this case.
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In the diagram, ATPR ~ AXPZ. Find the length of the altitude PY
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Two different lines lie in the same plane.
nikitadnepr [17]

Answer:

Two lines, both in the same plane, that never intersect are called parallel lines. Parallel lines remain the same distance apart at all times. The symbol // is used to denote parallel lines.

how to prove that two lines are equal: If two lines are cut by a transversal and the alternate exterior angles are equal, then the two lines are parallel. Angles can be equal or congruent; you can replace the word "equal" in both theorems with "congruent" without affecting the theorem. So if ∠B and ∠L are equal (or congruent), the lines are parallel.                                 therefore the answer is E. The two lines are everywhere equidistant.

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3 years ago
Read 2 more answers
Pears cost $0.92 per pound and apples cost $1.10 per pound. Mr. Bonilla bought 3.75 pound of pears and 2.1 pounds of apples. How
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Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th
Digiron [165]

Answer:

P(X = 0) = 0.0263

P(X = 1) = 0.1407

P(X = 2) = 0.3012

P(X = 3) = 0.3224

P(X = 4) = 0.1725

P(X = 5) = 0.0369

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.517

Distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263

P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407

P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012

P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224

P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725

P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369

6 0
4 years ago
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