where C is the circumference, d is the diameter and r is the radius.
The diameter of a circle is a line segment that passes through the center of the circle and has its endpoints on the circle. The radius of the circle is a line segment from the center of the circle to a point on the circle. The diameter of a circle is twice the length of its radius.
If you are given the diameter then use the formula C = πd
If you are given the radius then use the formula C = 2πr
Step-by-step explanation:
Answer:
This means that if you have that amount of those and you do whatever the rest of the question is.
Step-by-step explanation:
Answer:
ok so first you add all the prices together.
$9:00+$7:00+$8:00+$6:00+$4:00=34
then divide 34 by the number of prices.
34/5
then you get the mean
$6.8 is the mean
Step-by-step explanation:
<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.
From the figure it's clear that the area of shaded region will be the difference of areas of two circles.
Let the,
- Radius of smaller circle be r .
- Radius of smaller circle be r .
- Area of shaded region be
![\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}](https://tex.z-dn.net/?f=%5Cbf%20%5Cimplies%20Area_%7BShaded%7D%3D%20Area_%7Bbigger%7D-Area_%7Bsmaller%7D%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7BShaded%7D%20%3D%20%5Cpi%20R%5E2%20-%20%5Cpi%20r%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%28%20R%5E2-r%5E2%29%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%5B%20%2810cm%29%5E2%20-%20%284cm%29%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5B%20100cm%5E2-16cm%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cdfrac%7B22%7D%7B7%7D%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20%5Cboxed%7B%5Cred%7B%5Cbf%20Area_%7Bshaded%7D%20%3D%20264%20cm%5E2%20%7D%7D)
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<u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>
