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3 years ago

Measuring Angles. Please help me this is due at 11:59 today. Please and thank you

Mathematics

1 answer:

Mars2501 [29]3 years ago

4 0

Answer:

35 degrees

Step-by-step explanation:

2x+13+10x=145

2x+10x+13=145

12x+13=145

12x=145-13

12x=132

X=11

2×+13

(2×11)+13

22+13=35

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Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)

icang [17]

The equation is $y = \frac{3}{2} x - \frac{11}{2}$

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

So, the midpoint will be $(\frac{-1+7}{2} , \frac{1-5}{2} )\\\\$

= $(3,-2)$

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula $\frac{y_2-y_1}{x_2-x_1}$

The slope is $\frac{-5-1}{7+1}$ = $-\frac{2}{3}$

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of $-\frac{2}{3}$ is $\frac{3}{2}$

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

$-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}$

Thus, the equation becomes:

$y = \frac{3}{2} x - \frac{11}{2}$

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Step-by-step explanation:

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Step-by-step explanation:

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KATRIN_1 [288]

Answer:

Please let me know if your quadratic is $y=-2(x+2)^2+2$ .

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Step-by-step explanation:

It says vertex so I'm thinking you meant $y=-2(x+2)^2+2$ . Please correct me if I'm wrong.

The vertex form of a quadratic is $y=a(x-h)^2+k$ . It is called that because it tells you the vertex (h,k).

So if you compare the two forms you should see -h=2 while k=2.

-h=2 implies h=-2.

So the vertex is (h,k)=(-2,2).

To find the y-intercept, set x=0 and find y.

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Read 2 more answers

Measuring Angles. Please help me this is due at 11:59 today. Please and thank you​

Measuring Angles. Please help me this is due at 11:59 today. Please and thank you