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lisabon 2012 [21]
3 years ago
13

Help Find the lateral area of this pyramid whose base is an equilateral triangle. Its slant height is 14 ft and the length of ea

ch side of the triangular base is 6 ft. [? ] ft
Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

168 ft²

Step-by-step explanation:

The equation for the lateral area of a square pyramid is LA = (Pl/2)

Plug in the values LA = (24(14)) / 2

LA = 336/2

LA = 168 ft²

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Eva8 [605]

Answer:

1) x(x+7)

3) (x+5)*(x+4)

4) (x-6)*(x-8)

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6) 5(a-5)*(a+5)

7) (4x+3)*(2x-3)

8) 4( x²-6xy+8)

Step-by-step explanation:

4 0
3 years ago
What is the answer to 1.1x + 1.2x - 5.4 = -10
lord [1]
1.1x+1.2x-5.4=-10

11/10x+12/10x-54/10=10

11x/2.5+2^2-1*3/5x-3^3/5=-10

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11x+2(6x)+2(-27)/2*5=-10

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8 0
3 years ago
Read 2 more answers
What is the answer to f(x)=x^2-10x+4 f(-2)
Maru [420]

Answer:

Step-by-step explanation:

f(x)=4+20+4

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3 0
3 years ago
Use the figure to determine the intersection of planes EAB and EFG
vredina [299]

Answer:

Option (3). EF

Step-by-step explanation:

From the figure attached,

Plane defined by EAB can be represented by the face EABF of the square prism also.

Similarly, plane EFG can be represented by the face EFGH of the prism.

Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.

Therefore, intersection of the given planes is EF.

Option (3) will be the answer.

7 0
3 years ago
Given the system of equations:
kolezko [41]
2x=16-2y
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6(8-y)+4y=38
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y=5

8-5=x
x=3 <-Answer
4 0
3 years ago
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